Answer:
answer = 12.87 km/h
Step-by-step explanation:
Given
Ship A is sailing east at 25 km/h = 
ship B is sailing north at 20 km/h =
here x and y are the sailing at t = 4 : 00 pm for ship A and B respectively
so we get x = 4 ×25 =100 km/h
y = 4× 20 = 80 km/h
let z is the distance between the ships, we need to find 
at t = 4 hr
At noon, ship A is 130 km west of ship B (12:00 pm)
so equation will be
derivative first equation w . r. to t we get
![\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]](https://tex.z-dn.net/?f=%5Cfrac%7Bdz%7D%7Bdt%7D%20%3D%5Cfrac%7B1%7D%7Bz%7D%5B%28x%20-130%29%5Cfrac%7Bdx%7D%7Bdt%7D%20%2By%5Cfrac%7Bdy%7D%7Bdt%7D%5D)
Answer:
9/56 is your answer.
Step-by-step explanation:
[7+2(5 - 9)2]/[(4+1)2 - 3(22)=
[7+2(-4)2]/[(5)2-66]=
[7+2(-8)]/[10-66]=
(7+-16)/(-56)=
-9/-56=
9/56 is your answer.
14 ÷ 1/2 × 3 (I hope it's right. I would have done this)
1. If the matching ends are triangles, find the area of the triangle (A=1/2bh)
2. If Matching ends are rectangles/squares, find the area of the rectangle/square (bh)
Hope that was helpful!!!
$5912.50. To work out one percent of 5500 you divide it by 100 which makes 55. You then times that by 7.5 which makes 412.50. Add that onto 5500 and you get the answer.
