2 years ago

3a+4b=7ab Find the mistake and solve

Mathematics

1 answer:

alekssr [168]2 years ago

7 0

Answer:

The mistake is adding and there is no way to solve if you have to add

Step-by-step explanation:

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tekilochka [14]

Answer:

ASA

Step-by-step explanation:

In given triangle

Line BC = Line QR

Angle ABC = Angle PQR

Angle ACB = Angle PRQ

Computation:

Angle ABC = Angle PQR (Angle)

Line BC = Line QR (Side)

Angle ACB = Angle PRQ (Angle)

So,

ΔABC ≅ ΔPQR

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Yuron is sketching a scale drawing of a famous painting. The painting is 54 inches wide and 72 inches long. He used a scale fact

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The sketch was 36 inches wide

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suppose that the population of deer in a state is 1,500 and is growing 2% each year. Predict the population after 4 years

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3 years ago

In ΔGHI, the measure of ∠I=90°, the measure of ∠G=46°, and IG = 87 feet. Find the length of GH to the nearest tenth of a foot.

sergij07 [2.7K]

Answer:

See attached

I got an answer of 125.2411251548

or to the nearest tenth 125.2

Step-by-step explanation:

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2 years ago

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Suppose 10000 people are given a medical test for a disease. About1% of all people have this condition. The test results have a

Alina [70]

Answer:

The percent of the people who tested positive actually have the disease is 38.64%.

Step-by-step explanation:

Denote the events as follows:

X = a person has the disease

P = the test result is positive

N = the test result is negative

Given:

$P(X)=0.01\\P(P|X^{c})=0.15\\P(N|X)=0.10$

Compute the value of P (P|X) as follows:

$P(P|X)=1-P(P|X^{c})=1-0.15=0.85$

Compute the probability of a positive test result as follows:

$P(P)=P(P|X)P(X)+P(P|X^{c})P(X^{c})\\=(0.85\times0.10)+(0.15\times0.90)\\=0.22$

Compute the probability of a person having the disease given that he/she was tested positive as follows:

$P(X|P)=\frac{P(P|X)P(X)}{P(P)}=\frac{0.85\times0.10}{0.22} =0.3864$

The percentage of people having the disease given that he/she was tested positive is, 0.3864 × 100 = 38.64%.

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3 years ago