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Liula [17]
3 years ago
8

Write an equivalent expression of -2(1.5h+5)-4(-0.5+3h) without parenthesis

Mathematics
1 answer:
ryzh [129]3 years ago
8 0

The equivalent expression to given expression is: -15h-8

Step-by-step explanation:

We can simplify the given expression to find an equivalent expression.

Given expression is:

-2(1.5h+5)-4(-0.5+3h)

So by using distributive property

=-3h-10+2-12h\\=-15h-8

Hence,

The equivalent expression to given expression is: -15h-8

Keywords: Equivalent expressions, Polynomials

Learn more about polynomials at:

  • brainly.com/question/10552347
  • brainly.com/question/10570041

#LearnwithBrainly

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and point (1, 6). Substitute:

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6=4+b     <em>subtract 4 from both sides</em>

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A car salesperson sells a used car for $9,000 and earns 7, of the sale
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lilavasa [31]

Answer:

1. m=1/2

2. x=4/7

3. t=4

4. y=5

Step-by-step explanation:

1. 5m+4=7m+6

5m-7m=6-5

2m=1

m=1/2

2. -5x+3=2x-1

-5x-2x=-1-3

-7x=-4

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3. 5t-3=3t+5

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8 0
3 years ago
Read 2 more answers
A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the
Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= \pi r^2h

According to the problem,

\pi r^2 h=25

\Rightarrow h=\frac{25}{\pi r^2}

The surface area of the base of the can is = \pi r^2

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× \pi r^2)

The lateral surface area of the can is = 2\pi rh

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× 2\pi rh)

                                                 =\$2.5 \pi r h

Total cost of metal is C= 2.00 \pi r^2+2.5 \pi r h

Putting h=\frac{25}{\pi r^2}

\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}

\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}

Differentiating with respect to r

C'=4\pi r- \frac{62.5}{ r^2}

Again differentiating with respect to r

C''=4\pi + \frac{125}{ r^3}

To find the minimize cost, we set C'=0

4\pi r- \frac{62.5}{ r^2}=0

\Rightarrow 4\pi r=\frac{62.5}{ r^2}

\Rightarrow  r^3=\frac{62.5}{ 4\pi}

⇒r=1.71

Now,

\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0

When r=1.71 cm, the metal cost will be minimum.

Therefore,

h=\frac{25}{\pi\times 1.71^2}

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

6 0
3 years ago
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