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earnstyle [38]
4 years ago
6

Multiply: 1/6 * 2/3

Mathematics
2 answers:
Romashka [77]4 years ago
5 0
Problem⬇
1/6 (2/3)
Work⬇
1(2) / 6(3) = 2/18
Now, we get to your result for this problem
Your answer is 1/9
-----------------------------------------------------------------
1/6 × 2/3 = 1/9

☺

AnnZ [28]4 years ago
3 0
2/18 reduced = 1/9 that's my answer
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Please help me i need this asap
laiz [17]

Answer:

-2, -1

Step-by-step explanation:

B is the answer for you. Have a good day!

3 0
3 years ago
A ski lift is designed with a total load limit of 20,000 pounds. It claims a capacity of 100 persons. An expert in ski lifts thi
Yanka [14]

Answer:

0.5 = 50% probability that a random sample of 100 independent persons will cause an overload

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the sum of n values of a distribution, the mean is \mu \times n and the standard deviation is \sigma\sqrt{n}

An expert in ski lifts thinks that the weights of individuals using the lift have expected weight of 200 pounds and standard deviation of 30 pounds. 100 individuals.

This means that \mu = 200*100 = 20000, \sigma = 30\sqrt{100} = 300

If the expert is right, what is the probability that a random sample of 100 independent persons will cause an overload

Total load of more than 20,000 pounds, which is 1 subtracted by the pvalue of Z when X = 20000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 20000}{300}

Z = 0

Z = 0 has a pvalue of 0.5

1 - 0.5 = 0.5

0.5 = 50% probability that a random sample of 100 independent persons will cause an overload

5 0
3 years ago
Can someone please tell me why I got this wrong?
kvasek [131]
We have 
f(x)=<span>−x</span>²<span>+ 5x + 6
g(x)=</span><span>3x − 2

we know that
f(x)=g(x)
the solution is the intersection both graphs

using a graph tool
see the attached figure

the solution are the points
(4,10)
and
(-2,-8)

</span>

8 0
3 years ago
A bucket can hold a total of 5 gallons. If the bucket is 45% full, how much water is in the bucket?
kirill [66]

The question is an illustration of volume, and the amount of water in the bucket at 45% full is 2.25 gallons

<h3>How to determine the amount of water?</h3>

The capacity of the bucket is given as:

Bucket = 5 gallons

At 45% full, we have:

Capacity = 45% * 5 gallons

Evaluate the product

Capacity = 2.25 gallons

Hence, the amount of water in the bucket at 45% full is 2.25 gallons

Read more about volumes at:

brainly.com/question/1972490

#SPJ1

3 0
2 years ago
Find the slope and the y-intercept of the line. y=4x-5
dusya [7]

\bf \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}~\hspace{6em}\underset{y-intercept}{\stackrel{slope}{y=\stackrel{\downarrow }{4}x\underset{\uparrow }{-5}}}\qquad \qquad \begin{cases} slope\\ \qquad 4\\ y-intercept\\ \qquad (0,-5) \end{cases}

6 0
3 years ago
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