Answer:
Please find the answer in the explanation
Explanation:
Given that some plants were watered with 4 different types of water (salt water, regular water, sugar water and distilled water). After a two-week period, the height of the plants is measured.
1.) The Independent Variable (IV) are the different types of water
2)Dependent Variable (DV) are the height of the plant. Dependent variable depends on the independent variable.
3)Constant is the unchanged parameter which is the period - the two weeks
4)Control: is the quantity of water used.
Answer:
The resistance will be 2×R
Explanation:
We note that the resistivity of a cylindrical wire is given by the following relation;
Where:
ρ = Resistivity of the wire
R = The wire resistance
A = Cross sectional area of the wire = π·D²/4
L = Length of the wire
Rearranging, we have;
If the length and the diameter are both cut in half, we have;
L₂ = L/2
A₂ =π·D₂²/4 =
Therefore, the new resistance, R₂ can be expressed as follows;
Hence, the new resistance R₂ = 2×R, that is the resistance will be doubled.
When it says something like 'on the verge of moving,' it means that the pulling force and static friction force and gravitational force all cancel out! Any more pulling force and it is ready to move!
At some point, you want F as a function of <span>μs</span>, to determine the force needed depending on the coefficient of static friction. This function, <span>F(<span>μs</span>)</span>, will rely on the angle θ as well, but we want to consider just one angle θ in every scenario. One value means it is constant.
But if we know the F, and we know <span>μs</span>, we can find what the constant angle θ must be!
If F is the pulling force, <span>FS</span> is the static friction force, and <span>FG</span> is gravitational force,
<span><span><span>Fnet</span>=0</span><span>=F+<span>FS</span>+<span>FG</span></span><span>=F+<span>FN</span><span>μs</span>+mgsinθ</span><span>=F+mgcosθ<span>μs</span>+mgsinθ</span><span>=0</span></span>
Then you can find <span>F(<span>μs</span>)</span>, but then there is the issue of solving for the θ<span> to make it true.</span>
Logically both masses will collide and well make a reaction. first of all depending on the small mass it will either merge or unite with the big mass or it will bounce away from it . if this happen it will make a reaction that will affect both masses. Hope this helps if it is incorrect please let me know :)