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suter [353]
3 years ago
9

Two harmonic waves traveling in opposite directions interfere to produce a standing wave described by y = 3 sin (2x) cos 5t wher

e x is in m and t is in s. What is the wavelength of the interfering waves?
Physics
1 answer:
Nostrana [21]3 years ago
8 0

Answer:

The wavelength of the interfering waves is 3.14 meters.

Explanation:

Given that,

The equation of standing wave that is formed by interfering two harmonic waves (travelling opposite direction) is given by :

y=3\ sin(2x)\ cos(5t)........(1)

The general equation of standing wave is given by :

y=2A\ sin(kx)\ cos(\omega t)..............(2)

On comparing equation (1) and (2), we get :

k = 2

We know that,

\dfrac{2\pi}{\lambda}=k

\dfrac{2\pi}{\lambda}=2

\lambda=3.14\ m

So, the wavelength of the interfering wave is 3.14 meters. Hence, this is the required solution.      

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Answer:

Distance =  345719139.4[m]; acceleration = 3.33*10^{19} [m/s^2]

Explanation:

We can solve this problem by using Newton's universal gravitation law.

In the attached image we can find a schematic of the locations of the Earth and the moon and that the sum of the distances re plus rm will be equal to the distance given as initial data in the problem rt = 3.84 × 108 m

r_{e} = distance earth to the astronaut [m].\\r_{m} = distance moon to the astronaut [m]\\r_{t} = total distance = 3.84*10^8[m]

Now the key to solving this problem is to establish a point of equalisation of both forces, i.e. the point where the Earth pulls the astronaut with the same force as the moon pulls the astronaut.

Mathematically this equals:

F_{e} = F_{m}\\F_{e} =G*\frac{m_{e} *m_{a}}{r_{e}^{2}  } \\

F_{m} =G*\frac{m_{m}*m_{a}  }{r_{m} ^{2} } \\where:\\G = gravity constant = 6.67*10^{-11}[\frac{N*m^{2} }{kg^{2} } ] \\m_{e}= earth's mass = 5.98*10^{24}[kg]\\ m_{a}= astronaut mass = 100[kg]\\m_{m}= moon's mass = 7.36*10^{22}[kg]

When we match these equations the masses cancel out as the universal gravitational constant

G*\frac{m_{e} *m_{a} }{r_{e}^{2}  } = G*\frac{m_{m} *m_{a} }{r_{m}^{2}  }\\\frac{m_{e} }{r_{e}^{2}  } = \frac{m_{m} }{r_{m}^{2}  }

To solve this equation we have to replace the first equation of related with the distances.

\frac{m_{e} }{r_{e}^{2}  } = \frac{m_{m} }{r_{m}^{2} } \\\frac{5.98*10^{24} }{(3.84*10^{8}-r_{m}  )^{2}  } = \frac{7.36*10^{22}  }{r_{m}^{2} }\\81.25*r_{m}^{2}=r_{m}^{2}-768*10^{6}* r_{m}+1.47*10^{17}  \\80.25*r_{m}^{2}+768*10^{6}* r_{m}-1.47*10^{17} =0

Now, we have a second-degree equation, the only way to solve it is by using the formula of the quadratic equation.

r_{m1,2}=\frac{-b+- \sqrt{b^{2}-4*a*c }  }{2*a}\\  where:\\a=80.25\\b=768*10^{6} \\c = -1.47*10^{17} \\replacing:\\r_{m1,2}=\frac{-768*10^{6}+- \sqrt{(768*10^{6})^{2}-4*80.25*(-1.47*10^{17}) }  }{2*80.25}\\\\r_{m1}= 38280860.6[m] \\r_{m2}=-2.97*10^{17} [m]

We work with positive value

rm = 38280860.6[m] = 38280.86[km]

<u>Second part</u>

<u />

The distance between the Earth and this point is calculated as follows:

re = 3.84 108 - 38280860.6 = 345719139.4[m]

Now the acceleration can be found as follows:

a = G*\frac{m_{e} }{r_{e} ^{2} } \\a = 6.67*10^{11} *\frac{5.98*10^{24} }{(345.72*10^{6})^{2}  } \\a=3.33*10^{19} [m/s^2]

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The variables that Madison will have to deal with to test her hypothesis that increased concentrations of salt in the air speeds the corrosion of certain metals are as follows:

  • Independent variable: concentration of salt
  • Dependent variable: corrosion of metal

<h3>What are independent and dependent variables?</h3>

In an experiment, the independent variable is the variable that is changed or manipulated in a series of experiments.

On the other hand, a dependent variable is that outcome measured to see the effectiveness of the treatment.

According to this question, Madison makes an hypothesis that an increased concentrations of salt in the air speeds the corrosion of certain metals, the variables she should look out for are as follows:

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Learn more about variables at: brainly.com/question/1479694

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