First two rolls have to be 1-4 that is 2/3 chance twice and the third can be 4or 5
2/3*2/3*1/3 + the chance that the fourth is the 5 or 6.
2/3*2/3*2/3*1/3
So the solution is : P=2/3*2/3*1/3 + 2/3*2/3*2/3*1/3
Answer:
8+18+20x16 ,
Step-by-step explanation: yeah .
Answer:
dum there is part A prat B and C
Step-by-step explanation:
Answer:
2(lw+lh+wh)
Step-by-step explanation:
2(lw+lh+wh) using distributive property