1. The shape of cross-section is a circle.
2. The face parallel to ABCD is EFGH. Since this is a a rectangular shape,
A = L*H = 12*6 = 72 cm^2
3. The cross-section parallel to ABC is DEF with h = 12 ft, b= 5ft (where h is the height and b is the base of a right angled triangle).
Area, A = 1/2 *b*h = 1/2*5*12 =30 ft^2
4. Plane BDHF is a rectangle shape whose length is the diagonal of ABCD.
Diagonal BD = sqrt (AB^2+BD^2) = sqrt (8^2+7^2) = 10.63 cm.
Perimeter, P = 2(BD+DH) = 2(10.63+6) = 33.26 cm
Answer:
999
Step-by-step explanation:
this is the answer but I don't sure.
Answer:
x=7.48
Step-by-step explanation:
13^2+x^2=15^2
169+x^2=225
x^2=56
x=7.48
Answer:
-When (2×-5) intersects at ×-axis the value of × will be zero.
=>F(×)=× 0=2×-5
hence,
0,=2×-5
5=2×
=>×=5/2
Step-by-step explanation:
hpe it hlps
The area of a circle in terms of the circle's radius
is
Differentiating both sides with respect to
, you get
