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3 years ago

Which of the following technologies uses the results of a scientific discovery?

Computers and Technology

2 answers:

Lilit [14]3 years ago

5 0

Hello

D) will be your answer.

HOPE THIS HELPED :)

belka [17]3 years ago

4 0

D. All of these
Reason being, they wouldn't have been made if something hasn't been discovered about them.

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The leader of the team wants to do everything him or herself. They have a very big ego and are difficult to work with. What is t

JulijaS [17]

Answer:

The problem is the team leader thinks he/she is better than other team members?

Explanation:

He/She thinks or to show that no other team leader is as good as him/her.

7 0

3 years ago

Write a few statements that open a file called "greeting", write the message "hey!" to the file -- and then close it. declare an

pshichka [43]

C++:

int main () {

std::ofstream output {"greeting.txt"};
output << "hey!";
output.close();

return 0;
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6 0

3 years ago

Read 2 more answers

In which order does the processor search computer memory when it requires instruction or data?

skelet666 [1.2K]

Answer:

I think the answer is

Ram- Cache Memory-Hard disk

Explanation:

I hope this helps you

4 0

3 years ago

project-1 Write a class called Person that has two data members - the person's name and age. It should have an init method that

MArishka [77]

Hello how are you today

4 0

3 years ago

Suppose the daytime processing load consists of 65% CPU activity and 35% disk activity. Your customers are complaining that the

bekas [8.4K]

Answer:

The answer to this question can be described as follows:

Explanation:

Given data:

Performance of the CPU:

The Fastest Factor Fraction of Work:

$f_1=65 \% \\\\=\frac{65}{100} \\\\ =0.65$

Current Feature Speedup:

$K_1=$ 1.5

CPU upgrade=6000

Disk activity:

The quickest part is the proportion of the work performed:

Current Feature Speedup:

$k_2=3$

Disk upgrade=8000

System speedup formula:

$s=\frac{1}{(1-f)+(\frac{f}{k})}$

Finding the CPU activity and disk activity by above formula:

CPU activity:

$S_{CPU}=\frac{1}{(1-f_1)+(\frac{f_1}{k_1})} \\\\=\frac{1}{(1-0.65)+(\frac{0.65}{1.5})} \\\\=1.276 \% ...\rightarrow (1) \\$

Disk activity:

$S_{DISK} = (\frac{1}{(1-f_2)+\frac{f_2}{k_2}}) \\\\ S_{DISK} = (\frac{1}{(1-0.35)+\frac{0.35}{3}}) \\\\ = -0.5\% .... \rightarrow (2)$

CPU:

Formula for CPU upgrade:

$= \frac{CPU \ upgrade}{S_{CPU}}\\\\= \frac{\$ 6,000}{1.276}\\\\= 4702.19....(3)$

DISK:

Formula for DISK upgrade:

$=\frac{Disk upgrade} {S_{DISK}}\\\\= \frac{\$ 8000}{-0.5 \% }\\\\= - 16000....(4)$

equation (3) and (4),

Thus, for the least money the CPU alternative is the best performance upgrade.

From (3) and (4) result,

The disc choice is therefore the best choice for a quicker system if you ever don't care about the cost.

The break-event point for the upgrades:

=4702.19 x-0.5

= -2351.095

From (2) and (3))

Therefore, when you pay the sum for disc upgrades, all is equal $ -2351.095

4 0

3 years ago