Does peterson's solution to the mutual-exclusion problem shown in fig. 2-24 work when process scheduling is preemptive

1 answer:

4 0

Yes. Not only does Peterson's Solution work with preemptive scheduling, but it was designed for that very case. In fact, when scheduling is non-preemptive, there is a possibility it might fail. For example, in a case where 'turn' is initially 0, but process 1 runs first, it will loop perpetually, and never release the CPU.

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Item

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If a cytosine base is substituted for by a thymine base in a DNA segment during DNA replication, the sequence could code for the wrong amino acid during translation.

The change in the sequence of DNA is known as mutation.

When a base substitution occurs in the sequence of a DNA during replication, the genetic information in the region where the substitution occurred becomes compromised.

During transcription, the process of encoding genetic information on DNA into RNA, the base substituted is also transcribed along. If cytosine is substituted by thymine, adenine is transcribed instead of guanine.

During the translation of the genetic codes, the wrong amino acids might end up being translated due to the substituted base, leading to a faulty protein.

More on mutation can be found here: brainly.com/question/4347425

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