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Viktor [21]
3 years ago
9

Why your body feels like it is being pushed back when the car starts back up again?

Chemistry
1 answer:
prisoha [69]3 years ago
5 0

That is the result of Newton's 3rd law of motion, which is inertia. Your body wants to remain at rest as the car accelerates, and the car has to push on you to get you moving. This is why you feel like you're actually being pushed forward, unless you're accelerating backward. It is the exact same reason you tend to lean while cornering, as well. Also, when you brake, this is why you tend to feel like you're being pulled foreword. Inertia is the tendency for things at rest to stay at rest until an outside force acts upon it. Also, a body in motion tends to want to stay in motion (in a straight line) until an outside force acts upon it to change it.

-google

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Elements of the same group show similar chemical properties as they have the same number of valence electrons. Sulfur belongs to the group 16 or 6 A or the oxygen family with 6 valence electrons. The elements of group 6 A are Oxygen, Sulfur, Selenium, Tellurium and Polonium. All of these elements show similar chemical properties. Therefore, when a biochemist studying the properties a sulfur containing biochemical compounds in the body wants to look at any other non-metal with similar properties, he has to consider other elements of the group 6 A like Oxygen (O), Selenium (Se), Tellurium (Te) and Polonium (Po).

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3 years ago
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Write the balanced standard combustion reaction for the c5h7on3s2
AlexFokin [52]

Answer:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Explanation:

When C5H7ON3S2 under go Combustion, the following are obtained as illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

Now, let us balance the equation. This is illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

There are 3 atoms of N on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of C5H7ON3S2 and 6 in front of N2 as shown below:

4C5H7ON3S2 + O2 —> CO2 + H2O + 6N2 + S2

There are 20 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 20 in front of CO2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + H2O + 6N2 + S2

There are 28 atoms on H on the left side and 2 atoms on the right side. It can be balance by putting 14 in front of H2O as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + S2

There are 8 atoms of S on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of S2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, there are a total of 54 atoms of O on the right side and 6 atoms on the left side

It can be balance by putting 25 in front of O2 as shown below:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, we can see that the equation is balanced.

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Answer:

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