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Viktor [21]
3 years ago
9

Why your body feels like it is being pushed back when the car starts back up again?

Chemistry
1 answer:
prisoha [69]3 years ago
5 0

That is the result of Newton's 3rd law of motion, which is inertia. Your body wants to remain at rest as the car accelerates, and the car has to push on you to get you moving. This is why you feel like you're actually being pushed forward, unless you're accelerating backward. It is the exact same reason you tend to lean while cornering, as well. Also, when you brake, this is why you tend to feel like you're being pulled foreword. Inertia is the tendency for things at rest to stay at rest until an outside force acts upon it. Also, a body in motion tends to want to stay in motion (in a straight line) until an outside force acts upon it to change it.

-google

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Which of the following correctly describes a mixture? (4 points) Group of answer choices The particles are chemically bonded tog
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Answer:

The particles have no set ratio for how to combine, and they can be separated by physical means.

Explanation:

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3 years ago
Given the problem below, what would the first step be in solving it?
Hoochie [10]

Answer:

First step would be convert to moles

Final Answer: 37.8 g of NaCl

Explanation:

The reaction is:

2Na + Cl₂ → 2NaCI

We convert the mass of each reactant to moles:

18 g . 1mol /23g = 0.783 moles of Na

23g . 1mol / 70.9g = 0.324 moles of chlorine

We use the mole ratio to determine the limiting reactant:

Ratio is 2:1. 2 moles of Na react to 1 mol of chlorine

Then, 0.783 moles of Na, may react to (0.783 . 1)/2 = 0.391 moles.

Excellent!. We need 0.391 moles of Cl₂ and we only have 0.324 moles available. That's why the Cl₂ is our limiting reactant.

We use the mole ratio again, with the product side. (1:2)

1 mol of Cl₂ can produce 2 moles of NaCl

Then, our 0.324 moles of gas, may produce (0.324 . 2)/1 = 0.648 moles

Finally, we convert the moles to grams:

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4 0
3 years ago
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3 years ago
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Answer:

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8 0
2 years ago
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Answer:

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A)1935J

Explanation:

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3 years ago
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