Answer:
The answer to your question is m = 4.7 kg
Explanation:
Data
Ice Water
mass = ? mass = 711 g
T₁ = -13°C T₁ = 87°C
T₂ = 10°C T₂ = 10°C
Ch = 2090 J/kg°K Cw = 4180 J/kg°K
Process
1.- Convert temperature to kelvin
T₁ = 273 + (-13) = 260°K
T₁ water = 87 + 273 = 360 °K
T₂ = 10 + 273 = 283°K
2.- Write the equation of interchange of heat
- Heat lost = Heat absorbed
- mwCw(T₂ - T₁) = miCi(T₂ - T₁)
-Substitution
- 0.711(4180)(10 - 87) = m(2090)(10 - (-13))
- Simplification
228842.46 = 48070m
m = 228842.46/48070
-Result
m = 4.7 kg
The keg for the reaction
2 SO2(g) + O2(g) → 2 SO3(g) is
Keg = [SO3]^2/ {(SO2)^2 ( O2)}
Keg (equilibrium constant) is the ratio of of equilibrium concentration of the product raised to the power of their stoichiometric coefficient to the equilibrium concentration of the reactant raised to the power of their stoichiometric coefficient.
Answer:
See explanation
Explanation:
The balanced redox reaction equation is;
8H+ + MnO4^- + 5Fe2+ ---------> Mn2+ + 5Fe3+ + 4H2O
Amount of KMnO4 reacted = 31.60/1000 * 0.05120 = 1.62 * 10^-3 moles
From the reaction equation;
1 mole of MnO4^- reacted with 5 moles of Fe2+
1.62 * 10^-3 moles will react with 1.62 * 10^-3 moles * 5/1 = 8.1 * 10^-3 moles
Mass of Fe2+ reacted = 8.1 * 10^-3 moles * 56 g/mol
Mass of Fe2+ reacted = 0.45 g
Amount of iron in the sample = 0.45 g
Percentage of iron in the sample;
0.45 g/4.230 g * 100 = 10.6 %
