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Damm [24]
3 years ago
10

Which is true about each element in a period or horizontal row of the periodic table?

Chemistry
1 answer:
Ber [7]3 years ago
3 0

The  true  about element in  period or  horizontal  row  of periodic table is

Each  element  has one more outer electron than the element before it. (answer B)

<u><em>  Explanation</em></u>

 In periodic table  there are four horizontal rows(periods) that is  period 1,2,3 and 4.

Across the period each element has one more electron than element before it.

For example  Na and Mg which  are in  periodic 3.

Na  has 2.8.1  or [Ne] 3s¹ electron configuration  while Mg has  2.8.2  or [Ne] 3S² electron configuration.

Since Mg has 2   outer electrons  while Na has 1 outer electron, Mg has more electron than Na.

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Why can’t you perform single displacement reactions with group IA metals?
pishuonlain [190]
Answer is: because alkaline metals (group IA metals) are the strongest reducing agents and most reactive metals.
Reducing agent<span> is an element  or compound that loses an </span>electron<span> to another </span>chemical species<span> in a </span>redox <span>chemical reaction and they have been oxidized.
Alkaline metals tend to lose only one electron in redox reaction.</span>
5 0
3 years ago
How many liters of 3.5 M solution can be made using 23 moles of LiBr *must show work to get credit*
MrMuchimi

<u>Answer:</u> 6.57 L of solution can be made.

<u>Explanation:</u>

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

\text{Molarity of solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (L)}} .....(1)

Given values:

Molarity of LiBr = 3.5 M

Moles of LiBr = 23 moles

Putting values in equation 1, we get:

3.5mol/L=\frac{23mol}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{23mol}{3.5mol/L}=6.57L

Hence, 6.57 L of solution can be made.

5 0
3 years ago
Which of the following is not capable of reacting with molecular oxygen?
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8 0
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Read 2 more answers
If 10.g of AgNo3 is available, what volume of 0.25 M AgNo3 can be prepared
Marianna [84]
The equation is L = m/M
First, covert 10. grams of AgNO3 to moles which is 0.059 moles.
Divide 0.059 moles by 0.25M which is 0.24 liters.
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