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vampirchik [111]
4 years ago
6

How many moles of oxygen are produced when 29.2 g of water is decomposed according to H20 H2 + O2​

Chemistry
1 answer:
Katarina [22]4 years ago
5 0

8.1moles

Explanation:

Given parameters:

Mass of water to be decomposed = 29.2g

Unknown:

Number of moles of oxygen.

Solution:

To solve this problem, we first write the balanced reaction equation :

               2H₂O    →     2H₂    +    O₂

Now convert the given mass of the water to number of moles;

  Number of moles of water = \frac{mass}{molar mass}

 

  Molar mass of water = 2(1) + 16 = 18g/mol

  Number of moles of water = \frac{29.2}{18}  = 16.2moles

   From the balanced reaction equation:

   2 moles of water produced 1 mole of oxygen gas;

   16.2 mole of water will produce   \frac{16.2}{2}  = 8.1moles of oxygen gas

learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

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If the actual yield of a reaction is 37.6 g while the theoretical yield is 112.8 g what is the percent yield
Zigmanuir [339]
<h2>Hello!</h2>

The answer is:

The percent yield of the reaction is 32.45%

<h2>Why?</h2>

To calculate the percent yield, we have to consider the theoretical yield and the actual yield. The theoretical yield as its name says is the yield expected, however, many times the difference between the theoretical yield and the actual yield is notorious.

We are given that:

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Now, to calculate the percent yield, we need to divide the actual yield by the theoretical and multiply it by 100.

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Have a nice day!

8 0
4 years ago
Read 2 more answers
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