Answer:
See explaination
Explanation:
#include <iostream>
using namespace std;
void SelectionSortDescendTrace(int numbers[], int numElems) {
int maxInd;
for (int i = 0; i < numElems - 1; ++i) {
maxInd = i;
for (int j = i; j < numElems; ++j) {
if (numbers[j] > numbers[maxInd]) {
maxInd = j;
}
}
int temp = numbers[i];
numbers[i] = numbers[maxInd];
numbers[maxInd] = temp;
for (int j = 0; j < numElems; j++) {
cout << numbers[j] << " ";
}
cout << endl;
}
}
int main() {
int numbers[10];
int numElements = 0;
for (int i = 0; i < 10; i++) {
cin >> numbers[i];
if (numbers[i] == -1)
break;
++numElements;
}
SelectionSortDescendTrace(numbers, numElements);
return 0;
}
Answer:
Aaron could expect a diversity in the style of the sheep drawings.
Explanation:
Crowdsourcing is a simply a sourcing model in which an individual or organizations get goods and services, ideas and finances, from a large, relatively open and often rapidly growing group of internet users.
It makes it easier for participants to achieve a cumulative result through working differently on the same project. That is to say, it provides work between participants to achieve a cumulative result.
Its benefits is that, Crowdsourcing allows businesses to perform tasks more quickly than when a single employee is working alone. Again, Breaking up a project into a collection of smaller pieces and providing these pieces to a larger group of workers hastens the completion of projects. Overall, crowdsourcing presents a more efficient way to do work.
From the Question, Aaron was able to get different pictures of sheep in their numbers also because he used crowsourcing on amazon.
He got a variety of pictures and so many in such a short time for his project "The Sheep Market".
Technology is what we use today to access internet and social media!!!
Answer:
(a) What is the best case time complexity of the algorithm (assuming n > 1)?
Answer: O(1)
(b) What is the worst case time complexity of the algorithm?
Answer: O(n^4)
Explanation:
(a) In the best case, the if condition will be true, the program will only run once and return so complexity of the algorithm is O(1)
.
(b) In the worst case, the program will run n^4 times so complexity of the algorithm is O(n^4).
import turtle
window = turtle.Screen()
tr = turtle.Turtle()
tr.forward(100)
tr.left(90)
tr.forward(100)
tr.left(90)
tr.forward(100)
tr.left(90)
tr.forward(100)
tr.back(100)
tr.left(120)
tr.forward(75)
tr.right(78)
tr.forward(60)
window.mainloop()
In my code, we use the turtle module for the graphics to draw the house with a roof.
