Answer:
The block+bullet system moves 4 m before being stopped by the frictional force.
Explanation:
Using the law of conservation of llinear momentum and the work energy theorem, we can obtain this.
According to Newton's second law of motion
Momentum before collision = Momentum after collision
Momentum before collision = (0.02×400) + 0 (stationary block)
Momentum before collision = 8 kgm/s
Momentum after collision = (2+0.02)v
8 = 2.02v
v = 3.96 m/s.
According to the work-energy theorem,
The kinetic energy of the block+bullet system = work done by Friction to stop the motion of the block+bullet system
Kinetic energy = (1/2)(2.02)(3.96²) = 15.84 J
Work done by the frictional force = F × (distance moved by the force)
F = μmg = 0.2(2.02)(9.8) = 3.96 N
3.96d = 15.84
d = (15.84/3.96) = 4 m
Answer: 160 m
Explanation: First find time or t using the formula for acceleration:
a = vf - vi / t
So t is equal to:
t = vf - vi / a
= 0 m/s - 20 m/s / -2.5 m/s²
= 8 s
To find the distance use the formula for velocity:
v = d / t
Derive for d:
d = v x t
= 20 m/s x 8 s
= 160 m
Answer:
Salty Water
Explanation:
Swimming in Salty water gives us more buoyancy when freshwater does not.
B. The amount of work done by the worker on the wheelbarrow is 250 J.
<h3>Work done by the worker</h3>
The amount of work done by the worker on the wheelbarrow is calculated as follows;
W = Fd
where;
- F is applied force
- d is displacement
W = 50 x 5
W = 250 J
Thus, the amount of work done by the worker on the wheelbarrow is 250 J.
Learn more about work done here: brainly.com/question/8119756
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