ILL GIVE BRAINLYEST

A wire is formed into a circle having a diameter of 11.1 cm and is placed in a uniform magnetic field of 2.79 mT. The wire carri

Ber [7]

Answer:

Maximum torque on the wire is $1.34\times 10^{-4}\ N-m$

Explanation:

It is given that,

Diameter of the wire, d = 11.1 cm = 0.111 m

Radius of wire, r = 0.0555 m

Magnetic field, $B=2.79\ mT=0.00279\ T$

Current, I = 5 A

We need to find the maximum torque on the wire. Torque is given by :

$\tau=IAB\ sin\theta$

Torque is maximum when, $\theta=90$

$\tau=IAB$

$\tau=5\times \pi \times (0.0555)^2\times 0.00279$

$\tau=0.000134\ N-m$

or

$\tau=1.34\times 10^{-4}\ N-m$

So, the maximum toque on the wire is $1.34\times 10^{-4}\ N-m$ . Hence, this is the required solution.

6 0

3 years ago

Four +2 µC point charges are at the corners of a square of side 2 m. Find the potential at the center of the square (relative to

Romashka [77]

Answer:

(a) 51428.59 J/C

(b) 25714.29 J/C

(c) 0 J/C

Explanation:

Parameters given:

Q1 = 2 * 10^-6 C

Q2 = 2 * 10^-6 C

Q3 = 2 * 10^-6 C

Q4 = 2 * 10^-6 C

=> Q1 = Q2 = Q3 = Q4 = Q

Side of the square = 2m

The center of the square is the midpoint of the diagonals, i.e. Using Pythagoras theorem:

BD² = 2² + 2²

BD² = 8

BD = √(8) = 2.8m

OD = 1.4m

(The attached diagram explains better)

Hence, the distance between the center and each point charge, r, is 1.4m.

Electric Potential, V = kQ/r

k = Coulombs constant

(a) If all charges are positive:

V(Total) = V1 + V2 + V3 + V4

V1 = Potential due to Q1

V2 = Potential due to Q2

V3 = Potential due to Q3

V4 =Potential due to Q4

Since Q1 = Q2 = Q3 = Q4 = Q

=> V1 = V2 = V3 = V4

=> V(Total) = 4V1

V = (4 * 9 * 10^9 * 2 * 10^-6)/1.4

V = 51428.59J/C

(b) If 3 charges are positive and 1 is negative:

Since Q1 = Q2 = Q3 = Q

and Q4 = -Q

The total potential becomes:

V(Total) = V1 + V2 + V3 - V4

Since V1, V2, V3 and V4 have the same value,

V(Total) = V1 + V2

V(Total) = 2V1

V(Total) = (2 * 9 * 10^9 * 2 * 10^-6)/1.4

V(Total) = 25174.29 J/C

(c) Two charges are positive and two are negative:

Since Q1 = Q2 = Q

and Q3 = Q4 = -Q

The total potential becomes:

V(Total) = V1 + V2 - V3 - V4

Since V1, V2, V3 and V4 have the same value,

V(Total) = 0 J/C

8 0

3 years ago

You are outdoors when you hear the constant chirp of a still cricket. You start walking toward the cricket and at some point you

givi [52]

Answer:

4) True, the distance was reduced by a de factor 2

Explanation:

To analyze the statements, let's first see how the sound is produced

The cricket makes the sound rubbed its legs, the energy needed to produce it is constant, after the sound is produced it expands in all directions and this wave is subject to the law of energy conservation.

By expanding in all directions we can assume that the energy for the time that is the power of the sound is distributed over a sphere with different radii each time. The perceived intensity is defined as the power per unit area

I = P / A

Where P is the power, A are the areas and I are the intensities heard by the person

Let's clear the power and match, for two different radii (distances)

P = I₁ A₁ = I₂ A₂

The area of a sphere is

A = 4π R₂

I₂ = I₁ A₁ / A₂

I₂ = I₁ 4π R₁² / 4π R₂²

I₂ = I₁ R₁² / R₂²

Let's analyze this last equation for the situation presented if the intensity increases 4 times, substitute

I₂ = 4 I₁

4 I₁ = I₁ R₁² / R₂²

R₂ = R₁ / 2

We see that to increase the intensity 4 times the distance was reduced twice

Now we can analyze the expressions given

2) False, the power is constant, the cricket always does the same job

3) False, the speed of the wave is constant in the air

4) True, the distance was reduced by a de factor 2

3 0

3 years ago

Which type of image is formed on a cinema screen?

Taya2010 [7]

Answer:

A real image is formed on a cinema screen.

Explanation:

It is a type of image that is formed when light rays coming from an object meet each other in actual after reflection or refraction. A real image can be easily obtained on the screen. It is always inverted

5 0

3 years ago

What effect does the Sun have on the ocean tides?

Degger [83]

Answer:

B

Explanation:

When the sun, moon, and Earth are in alignment at the time of the new or full moon, the solar tide has an additive effect on the lunar tide, creating extra-high high tides, and very low, low tides both commonly called spring tides.

8 0

3 years ago