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4 years ago

ILL GIVE BRAINLYEST

Physics

1 answer:

lawyer [7]4 years ago

5 0

Answer:

3rd picture straight line going up right

Explanation:

3rd picture

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a. A beam of light is incident from air on the surface of a liquid. If the angle of incidence is 26.7° and the angle of refracti

Diano4ka-milaya [45]

Answer:

(a). The critical angle for the liquid when surrounded by air is 44.37°

(b). The angle of refraction is 26.17°.

Explanation:

Given that,

Incidence angle = 26.7°

Refraction angle = 18.3°

(a). We need to calculate the refraction of liquid

Using Snell's law

$n=\dfrac{\sin i}{\sin r}$

Put the value into the formula

$n=\dfrac{\sin 26.7}{\sin 18.3}$

$n=1.43$

We need to critical angle for the liquid when surrounded by air

Using formula of critical angle

$C=\sin^{-1}(\dfrac{1}{n})$

Put the value into the formula

$C=\sin^{-1}(\dfrac{1}{1.43})$

$C=44.37^{\circ}$

(b). Given that,

Incidence angle = 37.5°

Speed of light in mineral $v=2.17\times10^{8}\ m/s$

We need to calculate the index of refraction

Using formula of index of refraction

$n=\dfrac{c}{v}$

Put the value into the formula

$n=\dfrac{3\times10^{8}}{2.17\times10^{8}}$

$n=1.38$

We need to calculate the angle of refraction

Using Snell's law

$n=\dfrac{\sin i}{\sin r}$

$\sin r=\dfrac{\sin i}{n}$

Put the value into the formula

$\sin r=\dfrac{\sin 37.5}{1.38}$

$r=\sin^{-1}(\dfrac{\sin 37.5}{1.38})$

$r=26.17^{\circ}$

Hence, (a). The critical angle for the liquid when surrounded by air is 44.37°

(b). The angle of refraction is 26.17°.

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