Answer:
2.04 s
Explanation:
v = at + v₀
(-30.0 m/s) = (-9.8 m/s²) t + (-10.0 m/s)
t = 2.04 s
Explanation:
It is given that,
Mass of the rim of wheel, m₁ = 7 kg
Mass of one spoke, m₂ = 1.2 kg
Diameter of the wagon, d = 0.5 m
Radius of the wagon, r = 0.25 m
Let I is the the moment of inertia of the wagon wheel for rotation about its axis.
We know that the moment of inertia of the ring is given by :


The moment of inertia of the rod about one end is given by :

l = r


For 6 spokes, 
So, the net moment of inertia of the wagon is :


So, the moment of inertia of the wagon wheel for rotation about its axis is
. Hence, this is the required solution.
Answer:
The 80 mph car
Because the formula says 1/2 mass but for the velocity it is squared