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Sindrei [870]
3 years ago
14

When an object has a net force of zero, then it is said to be in what?

Physics
1 answer:
Ganezh [65]3 years ago
3 0

Answer: the object is said to be in a state of rest or uniform motion in a straight line

Explanation:Newton's first law of motion

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Which of these objects has the greatest inertia?
tangare [24]
The answer would be aircraft carrier
7 0
3 years ago
Compare and contrast infrasonic and ultrasonic vibrations
Olegator [25]

Answer:

Explanation:

Ultrasonic waves are acoustic waves that are so high in frequency that humans can't hear them; however, infrasonic waves are sound waves that are lower in frequency than what humans can hear. A subsonic wave is a wave that is traveling slower than the speed of sound and a supersonic waves travels faster

8 0
2 years ago
A 91.5 kg football player running east at 2.73 m/s tackles a 63.5 kg player running east at 3.09 m/s. what is their velocity aft
matrenka [14]

Answer:

The velocity of the players will be <u>2.88 m/s</u> in the <u>east</u> direction.

Explanation:

Let 'v' be the velocity of the players after collision.

Consider the east direction as positive direction.

Given:

Mass of the first player  is, m_1 = 91.5 kg  

Initial velocity of the first player  is, u_1 = 2.73 m/s  

Mass of the second player  is, m_2 = 63.5 kg  

Initial velocity of the second player is, u_2 = 3.09 m/s  

In order to solve this problem we use the law of conservation of momentum which says that the total momentum must be conserved before and after the collision. So we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1 + m_2)v

Solving for v, we get:

v = \frac{m_1 u_1+m_2 u_2}{m_1+m_2}=\frac{(91.5)(2.73)+(63.5)(3.09)}{91.5+63.5}=2.88\ m/s

Therefore, their velocity after the collision is 2.88 m/s.

The sign of the velocity after collision is positive. So, the players will move in the east direction only after collision.

3 0
3 years ago
A 1.2-kg ball drops vertically onto the floor, hitting with a speed of 25 m/s. Consider the impulse during this collision. Would
Ksju [112]

Answer:

3kg

Explanation:

impulse = MV

then

m1v1=m2v2

when the values are subtitude

then

m2=1.2*25/10

m2=<em>3</em><em>0</em><em>k</em><em>g</em><em>/</em><em>/</em>

7 0
3 years ago
Electrons in a particle beam each have a kinetic energy of 4.0 × 10 −17 J. What is the magnitude of the electric field that will
Dmitry_Shevchenko [17]

Answer:

-833.3 N/C

Explanation:

Kinetic energy, K, in terms of electric field, E, is given as:

K = qEr

q = charge = e = 1.6 × 10⁻¹⁹C

E = Electric field

r = distance = 0.3m

The electric field can be gotten by making E subject of formula:

E = K/(qr)

The electeic field needed to stop the electrons must be equal in magnitude to the electric field carried by these electrons:

E = (4.0 × 10⁻¹⁷)/(-1.6 × 10⁻¹⁹ * 0.3)

E = -833.3 N/C

This is the electric field needed to stop the electrons.

The negative sign means that the electric field must be in a direction opposite to the motion of the electrons.

3 0
3 years ago
Read 2 more answers
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