Answer:
The acceleration of the car, a = -3.75 m/s²
Explanation:
Given data,
The initial velocity of the airplane, u = 75 m/s
The final velocity of the plane, v = 0 m/s
The time period of motion, t = 20 s
Using the I equations of motion
v = u + at
a = (v - u) / t
= (0 - 75) / 20
= -3.75 m/s²
The negative sign indicates that the plane is decelerating
Hence, the acceleration of the car, a = -3.75 m/s²
Given:
u = 0, initial speed (sprinter starts from rest)
v = 11.5 m/s, final speed
s = 15 m, distance traveled to attain final speed.
Let
a = average acceleration,
t = time taken to attain final speed.
Then
v² = u² + 2as
or
(11.5 m/s)² = 2*(a m/s²)*(15 m)
a = 11.5²/(2*15) = 4.408 m/s²
Also
v = u +a t
or
(11.5 m/s) = (4.408 m/s²)*(t s)
t = 11.5/4.408 = 2.609 s
Answer:
The average acceleration is 4.41 m/s² (nearest hundredth).
The time required is 2.61 s (nearest hundredth).
Answer:
a cornea that is not curved enough
Answer:
v = 0.33 m/s
Explanation:
The final velocity of the skier and boat can be calculated by conservation of the lineal momentum:
<u>Where:</u>
m1: is the mass of the water skier = 62.0 kg
m2: is the mass of the boat = 775 kg
v1i: is the initial velocity of the water skier = 4.50 m/s
v1f: is the final velocity of the water skier = ?
v2i: is the initial velocity of the boat = 0
v2f: is the final velocity of the boat = ?
Since the final velocity of the skier is the same that the final velocity of the boat, we have:
Therefore, the final velocity of the skier and boat is 0.33 m/s.
I hope it helps you!
Answer:
144 cm²
Explanation:
In dividing to 8 cubes the side of a cube will be 2 cm.
It can be taken by volume as
4×4×4 = 8×(l×l×l) where l = length of the cube required.
So surface area of a small cube is 6×(2×2) = 24 cm²
Six such cubes will have a surface area of 144 cm²
