April sold 75 tickets to the school Christmas play and collected $495. If adult tickets cost $8 and children tickets were $5 how
1 answer:
40 adult tickets were sold and 35 children tickets were sold
<em><u>Solution:</u></em>
Let "a" be the number of adult tickets sold
Let "c" be the number of children tickets sold
Cost of 1 adult ticket = $ 8
Cost of 1 children ticket = $ 5
<em><u>Given that April sold 75 tickets to the school Christmas play and collected $495</u></em>
Number of tickets sold = 75
number of adult tickets sold + number of children tickets sold = 75
a + c = 75 ----- eqn 1
<em><u>Given that April collected $495</u></em>
Thus we can frame a equation as:
number of adult tickets sold x Cost of 1 adult ticket + number of children tickets sold x Cost of 1 children ticket = $ 495
8a + 5c = 495 ----- eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>
From eqn 1,
a = 75 - c ---- eqn 3
Substitute eqn 3 in eqn 2
8(75 - c) + 5c = 495
600 - 8c + 5c = 495
-3c = 495 - 600
-3c = - 105
<h3>c = 35</h3>Substitute c = 35 in eqn 3
a = 75 - 35
<h3>a = 40</h3>Thus 40 adult tickets were sold and 35 children tickets were sold
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