April sold 75 tickets to the school Christmas play and collected $495. If adult tickets cost $8 and children tickets were $5 how
1 answer:
40 adult tickets were sold and 35 children tickets were sold
<em><u>Solution:</u></em>
Let "a" be the number of adult tickets sold
Let "c" be the number of children tickets sold
Cost of 1 adult ticket = $ 8
Cost of 1 children ticket = $ 5
<em><u>Given that April sold 75 tickets to the school Christmas play and collected $495</u></em>
Number of tickets sold = 75
number of adult tickets sold + number of children tickets sold = 75
a + c = 75 ----- eqn 1
<em><u>Given that April collected $495</u></em>
Thus we can frame a equation as:
number of adult tickets sold x Cost of 1 adult ticket + number of children tickets sold x Cost of 1 children ticket = $ 495
8a + 5c = 495 ----- eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>
From eqn 1,
a = 75 - c ---- eqn 3
Substitute eqn 3 in eqn 2
8(75 - c) + 5c = 495
600 - 8c + 5c = 495
-3c = 495 - 600
-3c = - 105
<h3>c = 35</h3>Substitute c = 35 in eqn 3
a = 75 - 35
<h3>a = 40</h3>Thus 40 adult tickets were sold and 35 children tickets were sold
You might be interested in
Answer:
We just add numerators and rewrite denominator.
Adding unlike dominators:
We need to find the same denominators. You need to find the least common multiple (LCM) of the two denominators.
Step-by-step explanation:
You mean unlike denominators and like denominators.
Adding like dominators: We just add numerators and rewrite denominator :
Example :
Adding unlike dominators:
We need to find the same denominators. You need to find the least common multiple (LCM) of the two denominators.
For example :
LCM for 5 and 4 is 20 : Now, divide by 5 and multiply by 1 for first fraction. 20 divide by 4 and multiply by 3 :