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statuscvo [17]
3 years ago
10

April sold 75 tickets to the school Christmas play and collected $495. If adult tickets cost $8 and children tickets were $5 how

many adult and children tickets were sold.
Mathematics
1 answer:
Ostrovityanka [42]3 years ago
8 0

40 adult tickets were sold and 35 children tickets were sold

<em><u>Solution:</u></em>

Let "a" be the number of adult tickets sold

Let "c" be the number of children tickets sold

Cost of 1 adult ticket = $ 8

Cost of 1 children ticket = $ 5

<em><u>Given that April sold 75 tickets to the school Christmas play and collected $495</u></em>

Number of tickets sold = 75

number of adult tickets sold + number of children tickets sold = 75

a + c = 75 ----- eqn 1

<em><u>Given that April collected $495</u></em>

Thus we can frame a equation as:

number of adult tickets sold x Cost of 1 adult ticket + number of children tickets sold x Cost of 1 children ticket = $ 495

a \times 8 + c \times 5 = 495

8a + 5c = 495 ----- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>

From eqn 1,

a = 75 - c ---- eqn 3

Substitute eqn 3 in eqn 2

8(75 - c) + 5c = 495

600 - 8c + 5c = 495

-3c = 495 - 600

-3c = - 105

<h3>c = 35</h3>

Substitute c = 35 in eqn 3

a = 75 - 35

<h3>a = 40</h3>

Thus 40 adult tickets were sold and 35 children tickets were sold

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→  (0.2)⁵  =  (1/5)⁵ = (1⁵ / 5⁵) =   \frac{1}{3125} .

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Method 2)

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(0.2)⁵ = 0.2 ×  0.2 × 0.2 × 0.2 × 0.2 ;

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      both "Method 1" and "Method 2" are equal:

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