April sold 75 tickets to the school Christmas play and collected $495. If adult tickets cost $8 and children tickets were $5 how
1 answer:
40 adult tickets were sold and 35 children tickets were sold
<em><u>Solution:</u></em>
Let "a" be the number of adult tickets sold
Let "c" be the number of children tickets sold
Cost of 1 adult ticket = $ 8
Cost of 1 children ticket = $ 5
<em><u>Given that April sold 75 tickets to the school Christmas play and collected $495</u></em>
Number of tickets sold = 75
number of adult tickets sold + number of children tickets sold = 75
a + c = 75 ----- eqn 1
<em><u>Given that April collected $495</u></em>
Thus we can frame a equation as:
number of adult tickets sold x Cost of 1 adult ticket + number of children tickets sold x Cost of 1 children ticket = $ 495
8a + 5c = 495 ----- eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>
From eqn 1,
a = 75 - c ---- eqn 3
Substitute eqn 3 in eqn 2
8(75 - c) + 5c = 495
600 - 8c + 5c = 495
-3c = 495 - 600
-3c = - 105
<h3>c = 35</h3>Substitute c = 35 in eqn 3
a = 75 - 35
<h3>a = 40</h3>Thus 40 adult tickets were sold and 35 children tickets were sold
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Answer:
There are 26 purple marbles in the bag.
Step-by-step explanation:
Firstly, you have to make an expression in terms of x where x represent red marbles. Given that the question says purple marbles is 2 more than 3 times the number of red marbles. So the expression is :
Let red marbles = x,
Next, given that the total marbles in the bag is 34 so you have to add both marbles together and solve the value of x :
Lastly, you have to substitute the value of x into the expression of purple marbles :
Let x = 8,
Answer:
12
Step-by-step explanation:
Use the pythagorean theorem (). A and b are the two legs of the triangle, and c is ALWAYS the hypotenuse. Plug in the values for a and c
Here's what I mean when I write <em>x/</em><em>2</em><em> </em><em>JUST </em><em>IN </em><em>CASE.</em>
а.
Let the total number of pencils be x, then this implies that Maggie received <em>x/</em>2 pencils from Katie. Maggie keeps 5 and give the rest to Jamil, this means
that Jamil receives
<em>x/</em>2-5 pencils.
b. Expression of pencils given to Jamil is: <em>x/</em>2-5
Substitute <em>x</em><em>=</em><em>1</em><em>6</em><em> </em>in this expression: <em>x/</em>2-5
Simplify and evaluate: = 8-5= 3
Maggie gives 3 pencils to Jamil.
c. Expression of pencils given to Jamil is: x/2-5 to
Equate this expression with 1 to form an equation and solve for <em>x</em> all, the total
number of pencils if Jamil received 1 pencil:
<em>x/</em>2 - 5 = 1
Solve for x:
<em>x</em> = 2(1+ 5)
Evaluate:
<em>x</em> = 2(6) = 12
Katie had 12 pencils if Jamil received 1 pencil.
RESULT
a. Expression of number of pencils given to Jamil is <em>x</em>/2-5, where x is total number of pencils.
b. Maggie gives 3 pencils to Jamil.
c. Katie had 12 pencils if Jamil received 1 pencil.
