Help me with this please ;(

Mathematics

2 answers:

emmasim [6.3K]2 years ago

7 0

If you count the cubes there are 5,
So as the question says we make it cubic units, so
5 cubic units.
Plz give me brainliest answer.
Hope it helps!

nadya68 [22]2 years ago

4 0

Answer:

5 cubes , so 5 cubic units

Step-by-step explanation:

There are 5 cubes in this figure.

Since each cube is a cubic unit, the answer is 5 cubic units.

-Chetan K

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2 years ago

Which simplified fraction is equal to 0.53 repeat ? A.24/46 B.8/15 C.42/90 D.5/9

murzikaleks [220]

Answer:

To see how these fractions are equal, I divided the numerators by the denominators. For instance, you could have 4 over 5 (4/5) and divide 4 by 5 (4/5) to get 0.8. Now you'll do the same thing for the fractions given

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8/15=0.533...

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Step-by-step explanation:

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3 years ago

Read 2 more answers

In the equation (x^2+y)^5, what is the coefficient of the term x^4y^3? what is the coefficient of the same term in the expansion

lys-0071 [83]

$\displaystyle
(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$

-------------------------------------------------------------

$\displaystyle
(x^2+y)^n=\sum_{k=0}^n\binom{n}{k}x^{2n-2k}y^k\\
n=5\\
k=3\\\\\binom{5}{3}=\dfrac{5!}{3!2!}=\dfrac{4\cdor5}{2}=10$

It's 10.

----------------------------------------------------

$\displaystyle
(3x^2+y)^n=\sum_{k=0}^n\binom{n}{k}(3x)^{2n-2k}y^k=\sum_{k=0}^n\binom{n}{k}\cdot 3^{2n-2k}\cdot x^{2n-2k}y^k\\\\
n=5\\
k=4\\\\
\binom{5}{3}\cdot3^{2\cdot5-2\cdot4}=10\cdot3^{2}=10\cdot9=90$