Answer:
Let x = software program
Let y = video game
x < 200 ; y < 300
x + y < 425
50x ; 35y
x = 200 ; y = 225
50(200) + 35(225) = 10,000 + 7,875 = 17,875
x = 125 ; y = 300
50(125) + 35(300) = 6,250 + 10,500 = 16,750
x = 175 ; y = 250
50(175) + 35(250) = 8,750 + 8,750 = 17,500
It is more profitable to maximize production of software program when working within the limits provided.
Step-by-step explanation:
Answer:
Ignacio can make 5 clockwise rotations.
Step-by-step explanation:
Given that the Ignacio's legs are already at a height of 49.3cm and each rotation of the chair knob raises his legs another 4.8cm, we can set up an inequality to determine the number of rotations Ignacio could make without his legs touching the desk, which is at a height of 74.5cm:
4.8r + 49.3 < 74.5 where 'r' is equal to the number of rotations
The sum of the Ignacio's original leg height plus the amount of height increased from the rotations of the know must be less than 74.5 in order for his legs not to touch. Now, solve for 'r':
Subtract 49.3 from both sides: 4.8r + 49.3 - 49.3 < 74.5 - 49.3 or 4.8r < 25.2
Divide 4.8 from both sides: 4.8r/4.8 < 25.2/4.8 or r < 5.25
Since the number of rotations must be less than 5.25, he can make 5 complete rotations.
Answer: Two planes meet in exactly one point
Two lines meet at exactly two points
Step-by-step explanation:
From the given statements there are two statements which are never true :-
1) Two planes meet in exactly one point .
Since when two line meets , they either meet at one point or infinite points (coincidence) , thus its impossible that they will meet at exactly two points.
2) Two lines meet at exactly two points
Since when two planes meet , the intersection of two plane always make a line not a point. Thus its impossible.
The amount of money, b, is $140.
Answer: Basically divide both number.
Step-by-step explanation:
Go to App sotr if u got iPhone or if u got android go to play store and download the app called PHOTOMATH and when u scan the answer it's gonna show the steps and the answer.
