Answer:
Step-by-step explanation:
C=2
Answer:
the answer is B
Step-by-step explanation:
Just estimate ex: 5 x 5 would be 25, so sqrt 22 would be just before the 5.
The standard form of a quadratic equation is

, while the vertex form is:

, where (h, k) is the vertex of the parabola.
What we want is to write

as

First, we note that all the three terms have a factor of 3, so we factorize it and write:

.
Second, we notice that

are the terms produced by

, without the 9. So we can write:

, and substituting in

we have:
![\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%20y%3D3%28x%5E2-6x-2%29%3D3%5B%28x-3%29%5E2-9-2%5D%3D3%5B%28x-3%29%5E2-11%5D)
.
Finally, distributing 3 over the two terms in the brackets we have:
![y=3[x-3]^2-33](https://tex.z-dn.net/?f=y%3D3%5Bx-3%5D%5E2-33)
.
Answer:
Answer:
First break up 72 into
36 x 2 x -1
Then take the square root of 36
6 square root 2 x -1
Finally make square root -1 = i
6i square root 2 is your answer
Step-by-step explanation:
1. There is no "h" in f(x) = log(x). The question is nonsense.
2. The log function is defined for arguments greater than zero. You're probably expected to select D, though A and B could also be correct.
3. Same deal. The log function is defined for x > -2, but the domain could be restricted to x > 2. You're expected to select FALSE.
4. Same deal. Choose B, though D is also correct.
5. C is the proper choice. (See discussion of the log function, above.)