Answer:
1.275 m
Explanation:
Let the maximum height reached be h.
Here initial velocity, u = 5 m/s
Final velocity, V = 0
Use third equation of motion
V^2 = u^2 + 2 g h
0 = 25 - 2 × 9.8 × h
h = 25/19.6 = 1.275 m
Answer:
33.33 m/sec
Explanation:
A baseball travels 200 metes in 6 seconds,
what is the baseball’s velocity?
use the formula: velocity = distance over time
where (d) distance = 200 m
and (t) time = 6 sec.
plugin values into the formula:
v = d / t
= 200 m / 6 sec
= 33.33 m/sec.
therefore, the baseball's velocity is 33.33 m/sec
Answer:
d = 19.796m
Explanation:
Since the ball is in the air for 4.02 seconds, the ball should reach the maximum point from the ground in half the total time, therefore, t=2.01s to reach maximum height. At the maximum height, the velocity in the y-direction is 0.
So we know t=2.01, vi=0, g=a=9.8m/s and we are solving for d.
Next, you look for a kinematic equation that has these parameters and the one you should choose is:

Now by substituting values in, we get
d = 19.796m