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Rudiy27
3 years ago
10

The resultant force acting on an object of mass 5.0kg varies with time as shown. the object is initially at rest.

Physics
1 answer:
il63 [147K]3 years ago
8 0
<span>particle varies with time as shown in the diagram. ... resultant has a magnitude equal to 8.0. .... A constant force F is applied to a body of mass m that initially is headed east at velocity .... If the resultant force acting on a 2.0-kg object is equal to ..... A ball of mass mB is released from rest and acquires velocity of magnitude vB ...</span><span>
</span>
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A particle with charge 3.20×10−19 c is placed on the x axis in a region where the electric potential due to other charges increa
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Answer:

-5 V

Explanation:

The charged particle (which is positively charged) moves from point A to B, and its kinetic energy increases: it means that the particle is following the direction of the field, so its potential energy is decreasing (because it's been converted into potential energy), therefore it is moving from a point at higher potential (A) to a point at lower potential (B). This means that the value

vb−va

is negative.

We can calculate the potential difference between the two points by using the law of conservation of energy:

\Delta K+ \Delta U=0\\\Delta K + q\Delta V=0

where:

\Delta K=+1.6\cdot 10^{-18} J is the change in kinetic energy of the particle

q=3.2\cdot 10^{-19} C is the charge of the particle

\Delta V =V_b-V_a is the potential difference

Re-arranging the equation, we can find the value of the potential difference:

\Delta V=V_b-V_a = -\frac{\Delta K}{q}=-\frac{1.6\cdot 10^{-18} J}{3.2\cdot 10^{-19} C}=-5 V

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3 years ago
In the first law of Thermodynamics ΔE = Q - W, what does ΔE stand for???
Alexxx [7]
<span>Δ</span>E = q + w

q = heat (quantity of)

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Explanation:

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Hope this helps!

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