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3 years ago

HELP ASAP PLEASE HELP!

Physics

2 answers:

ra1l [238]3 years ago

3 0

2. Because anything that can do work has energy

Maurinko [17]3 years ago

3 0

The answer is number 2 (I guess)

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Which one of the following accurately describes the force of gravity? A. The force of gravity is slightly lower at the bottom of

AfilCa [17]

Choice ' C ' is a correct statement.
The other choices aren't.

6 0

4 years ago

Light shines through a single slit whose width is 5.6 × 10-4 m. A diffraction pattern is formed on a flat screen located 4.0 m a

Mrac [35]

Answer:

462 nm

Explanation:

Given: width of the slit, d = 5.6 × 10⁻⁴ m

Distance of the screen, D = 4.0 m

Fringe width, β = 3.3 mm = 3.3 × 10⁻³ m

First dark fringe means n =1

Wavelength of the light, λ = ?

$\beta = \frac{\lambda D}{d}\\ \Rightarrow \lambda = \frac{d \beta}{D} =\frac{5.6\times 10^{-4} \times 3.3 \times 10^{-3}}{4.0} = 4.62 \times 10^{-7}m = 462 nm$

5 0

3 years ago

A ball is launched up a semicircular chute in such a way that at the top of the chute, just before it goes into free fall, the b

Mariulka [41]

We have centripetal acceleration = $v^2/r = 2g$

So, v = $\sqrt{2gr}$

Now by equation of motion we have S= ut +0.5a $t^2$

S =displacement, u = initial velocity, a= acceleration and t = time

Here S = 2r and a = g , u = 0

$2r = 0+\frac{1}{2} *g*t^2$

$t = \sqrt{\frac{4r}{g} }$

Distance traveled in horizontal direction = $\sqrt{2gr}*\sqrt{\frac{4r}{g} }= \sqrt{8r^2} =2r\sqrt{2}$

8 0

4 years ago

If the density of a diamond is 3.5 /cm^ 3 what would be the mass of a diamond whose volume is 0.5 cm ^ 3 ?

Elan Coil [88]

Answer:

1.75g

Explanation:

Given parameters:

Density = 3.5g/cm³

Volume = 0.5cm³

Unknown:

Mass of the diamond = ?

Solution:

Density is the mass per unit volume of a substance

Density = $\frac{mass}{volume}$

So;

Mass = 3.5 x 0.5 = 1.75g

7 0

3 years ago

The driver of a pickup truck accelerates from rest to a speed of 37 mi/hr over a horizontal distance of 215 ft with constant acc

ZanzabumX [31]

Answer:

Maximum shearing force developed in each of the two pegs during acceleration is 1830 lbf

Explanation:

First we will find the acceleration of pickup truck.

As, the acceleration is uniform, therefore we can use Newton's third equation of motion:

2as = $V_{f}^{2}-V_{i}^{2}$

First convert speed into ft/sec

1 mile/hr = 1.47 ft/sec

therefore,

37 mile/hr = 37 x 1.47 ft/sec

37 mile/hr = 54.39 ft/sec

with initial speed 0 ft/sec (starting from rest), using in equation of motion:

a = [(54.39 ft/sec)² - (0 ft/sec)²]/2(215 ft)

a = 6.88 ft/sec²

Now, the total shear force will be given by Newton's second law of motion:

F = ma

F = (460 lbm +72 lbm)(6.88 ft/sec²)

F = 3660 lbf

Now for the max shear force in each of the two pegs we divide total fore by 2:

Force in each peg = F/2 = (3660 lbf)/2

<u>Force in each peg = 1830 lbf</u>

6 0

3 years ago