The working equation to be used here is the Planck's equation. This was derived using the wave behavior theory of the light and electromagnetic waves. According to this equation, electron transfer from orbital to orbital in discrete packets of energy called quanta. When an electron moves to a higher energy level, it absorbs energy. On the other hand, when it lowers to an energy level, it releases energy by emitting light. Hence, the wavelength of the light or magnetic wave can be determined.
E = hν = hc/λ, where ν is the frequency, λ is the wavelength, h is the Planck's constant equal to 6.626×10⁻³⁴ J-s and c is the speed of light equal to 3×10⁸ m/s.
Knowing the energy to be 164 kJ or 164,000 J, the wavelength is equal to
164,000 = (6.626×10⁻³⁴)(3×10⁸ m/s)/λ
λ = 1.212×10⁻³⁰ meters
Answer:
0 degrees Celsius is 273 degrees Kelvin. As both pressure and volume are proportional to absolute temperature, in order to double both you would need to quadruple the temperature. I.e. 273 X 4 = 1092 Kelvin = 819 Celsius
Explanation:
Answer:
The correct answer is option 'c': Smaller stone rebounds while as larger stone remains stationary.
Explanation:
Let the velocity and the mass of the smaller stone be 'm' and 'v' respectively
and the mass of big rock be 'M'
Initial momentum of the system equals
Now let after the collision the small stone move with a velocity v' and the big roch move with a velocity V'
Thus the final momentum of the system is
Equating initial and the final momenta we get
Now since the surface is frictionless thus the energy is also conserved thus
Similarly the final energy becomes
\
Equating initial and final energies we get
Solving i and ii we get
Using this in equation i we get
Thus putting v = -v' in equation i we get V' = 0
This implies Smaller stone rebounds while as larger stone remains stationary.
The focus of an earthquake is internal and is harder to record than the waves of an epicenter, which are on the surface.
Answer: ??? D? dont quote me on it tho <3
Explanation:
