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3 years ago

C=ne 0.045=n 1.610^-19

Physics

1 answer:

bogdanovich [222]3 years ago

3 0

Math, solve fo n

0.045=n*1.6*10^-19
divide both sides by 1.6
0.028125=n*10^-19
divide both sides by 10^-19
0.028125*10^19=n
2.8125*10^17=n

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The force of magnitude F acts along the edge of the triangular plate. Determine the moment of F about point O. Find the general

Sever21 [200]

Answer:

The moment is 81.102 k N-m in clockwise.

Explanation:

Given that,

Force = 260 N

Side = 580 mm

Distance h = 370 mm

According to figure,

Position of each point

$O=(0,0)$

$A=(0,-b)$

$B=(h,0)$

We need to calculate the position vector of AB

$\bar{AB}=(h-0)i+(0-(-b))j$

$\bar{AB}=hi+bj$

We need to calculate the unit vector along AB

$u_{AB}=\dfrac{\bar{AB}}{|\bar{AB}|}$

$u_{AB}=\dfrac{h\hat{i}+b\hat{j}}{\sqrt{h^2+b^2}}$

We need to calculate the force acting along the edge

$\hat{F}=F(u_{AB})$

$\hat{F}=F(\dfrac{h\hat{i}+b\hat{j}}{\sqrt{h^2+b^2}})$

We need to calculate the net moment

$\hat{M}=\hat{F}\times OA$

Put the value into the formula

$\hat{M}=F(\dfrac{h\hat{i}+b\hat{j}}{\sqrt{h^2+b^2}})\times(-b\hat{j})$

$\hat{M}=\dfrac{F}{\sqrt{h^2+b^2}}((h\hat{i}+b\hat{j})\times(-b\hat{j}))$

$\hat{M}=\dfrac{F}{\sqrt{h^2+b^2}}(-bh\hat{k})$

$\hat{M}=-\dfrac{bhF}{\sqrt{h^2+b^2}}$

Put the value into the formula

$\hat{M}=-\dfrac{580\times10^{-3}\times370\times10^{-3}\times260}{\sqrt{(370\times10^{-3})^2+(580\times10^{-3})^2}}$

$\hat{M}=-81.102\ \hat{k}\ N-m$

Negative sign shows the moment is in clockwise.

Hence, The moment is 81.102 k N-m in clockwise.

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3 years ago

A mass of 100 kg is pulled by a 392 N force in the +X direction along a rough surface (uk=0.4) with uniform velocity v=20 m/s. W

alexdok [17]

Answer:

The total work done will be zero.

Explanation:

Given that,

Mass = 100 kg

Force = 392 N

Velocity = 20 m/s

Distance s= 10 m

We need to calculate the work done

Using balance equation

The net force will be

$F'=F-\mu mg$

$F'=392-0.4\times100\times9.8$

$F'=0$

The net force is zero.

Hence, The total work done will be zero by all forces on the object.

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2 years ago

Si una sustancia de 52 gramos de masa ,tiene un volumen de 2.5 cm,cual es la dendidad de la masa ?

yaroslaw [1]

Answer:

20.8g/cm³

Explanation:

Esta es la forma en inglés de la pregunta.

"Si una sustancia de 52 gramos de masa tiene un volumen de 2.5 cm³, ¿cuál es la densidad de la masa?"

La densidad se define como la relación entre la masa de una sustancia y su unidad de volumen.

Densidad = Masa / Volumen

Masa dada = 52 gramos

Volumen = 2.5cm³

Densidad = 52 / 2.5

Densidad de la sustancia = 20.8g / cm³

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Newton's second

Andru [333]

Explanation:

The second law states that the greater the mass of an object, the more force it will take to accelerate the object. There is even an equation that says Force = mass x acceleration or F=ma. This also means that the harder you kick a ball the farther it will go.

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2 years ago

PLEASE LOL I NEED IT NOW!

joja [24]

Answer:

Explanation:

I did this on edge an that was the answer

6 0

3 years ago

C=ne 0.045=n *1.6*10^-19

C=ne 0.045=n 1.610^-19