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iren [92.7K]
3 years ago
7

Quadrilateral ABCD has vertices A(1, -3) , B(2, 1), C(6, 3), and D(7, -1). Prove or disprove that the Quad ABCD is a rectangle.

Mathematics
1 answer:
zavuch27 [327]3 years ago
7 0
If AC=BD, than Quad ABCD is a rectangle
AC
√(3+3)²+(6-1)²
√6²+5²
√36+25
√61
BD
√(1+1)²+(2-7)²
√2²+(-5)²
√4+25
√29
Quad ABCD is not a rectangle because √61 and √29 are not equal.
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Bodmass<br><br>-3[2/6+8{-9/3(8-5*3)-6}]​
Vadim26 [7]

9514 1404 393

Answer:

  -361

Step-by-step explanation:

Your calculator can tell you the result. It is -361.

Start with the inner parentheses and work outward. Do multiplication and division in the order shown, left to right, before addition or subtraction.

  -3[2/6+8{-9/3(8-5*3)-6}]​

  = -3[2/6+8{-9/3(8-15)-6}]​

  = -3[2/6+8{-9/3(-7)-6}]​

  = -3[2/6+8{-3(-7)-6}]​

  = -3[2/6+8{21-6}]​

  = -3[2/6+8{15}]

  = -3[1/3+8{15}]

  = -3[1/3+120]

  = -3[361/3]

  = -361

8 0
3 years ago
When the distributive property is applied, which number completes the statement correctly?
maxonik [38]
-7, because you distribute it to both -4 and 3.2, which means you're multiplying it to both.
7 0
3 years ago
Please help me ASAP
V125BC [204]
I'd say it's "convergent and doesn't have a sum"

because it's multiplying by 3 to get every new number and switching between ± after every new number. there is no sum because it's an infinite series.
8 0
3 years ago
The product of 2r- t and 5m + 3=
DaniilM [7]

Answer: 10rm+6r-5tm-3t

Step-by-step explanation:

(2r-t)(5m+3)\\\\=10rm+6r-5tm-3t

7 0
2 years ago
It's 10 3/5 miles from Alsten to Barton and 12 1/2 miles from Barton to Chester. The distance from Alsten to Durbin,via Barton a
Ymorist [56]
10 3/5=10.6

10.6+12.5=23.1
35.0-23.1=11.9

It is 11.9 miles from Chester to Durbin.
4 0
3 years ago
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