Question

Quadrilateral ABCD has vertices A(1, -3) , B(2, 1), C(6, 3), and D(7, -1). Prove or disprove that the Quad ABCD is a rectangle.

Answer 1

If AC=BD, than Quad ABCD is a rectangle
AC
√(3+3)²+(6-1)²
√6²+5²
√36+25
√61
BD
√(1+1)²+(2-7)²
√2²+(-5)²
√4+25
√29
Quad ABCD is not a rectangle because √61 and √29 are not equal.