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iren2701 [21]
3 years ago
9

What is 0+0? Sayorana Tatake 2+2=?

Mathematics
2 answers:
VMariaS [17]3 years ago
5 0

Answer:

0 and 4

Step-by-step explanation:

0+0=0

2+2=4

hope this helps

irina [24]3 years ago
4 0

Answer:

1st one is 0, 2nd one is 4.

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Yuet solved the equation 6 a minus 2 b = 12 for a. Her steps are shown below. 1. Subtract 2b: 6 a = 12 minus 12 b 2. Divide by 6
Ber [7]

Question:

Yuet solved the equation 6a - 2b = 12 for a.

Her steps are shown below.

1. Subtract 2b: 6a = 12 - 2b

2. Divide by 6: a = 2 - \frac{b}{3}

Answer:

In step 1 she needed to add 2b to both sides of the equation.

Step-by-step explanation:

Given:

The above steps shows how Yuet solved an equation

Required:

True statement about Yuet's work

The implication of the statement is to state what Yuet should have done instead of what she did.

In step 1, she subtracted 2b from both sides of the equation; this is wrong.

Instead of subtracting, she ought to add 2b to both sides of the equation.

The correct steps and result is as follows:

1. Add 2b: 6a = 12 + 2b

2. Divide by 6: a = 2 + \frac{b}{3}

Hence, we can conclude that in step 1 she needed to add 2b to both sides of the equation.

4 0
3 years ago
Read 2 more answers
5x + 2(x + 7) = 14x – 7
iren2701 [21]

Answer: X=3

Step-by-step explanation:

5x+2x+14=14x-7

7x+14=14x-7

7x-14x=-7-14

-7x=-21

x=3

5 0
3 years ago
Two nickels are flipped and a number cube is rolled. How many total outcomes are there?
Taya2010 [7]

Answer:

2

Step-by-step explanation:

3 0
3 years ago
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Provide conditions under which the mean function is linear but has a negative coefficient
den301095 [7]
Depending on your dependent/outcome variable, a negative value for your constant/intercept should not be a cause for concern. This simply means that the expected value on your dependent variable will be less than 0 when all independent/predictor variables are set to 0. For some dependent variables, this would be expected. For example, if the mean value of your dependent variable is negative, it would be no surprise whatsoever that the constant is negative; in fact, if you got a positive value for the constant in this situation, it might be cause for concern (depending on your independent variables).Even if your dependent variable is typically/always positive (i.e., has a positive mean value), it wouldn't necessarily be surprising to have a negative constant. For example, consider an independent variable that has a strongly positive relationship to a dependent variable. The values of the dependent variable are positive and have a range from 1-5, and the values of the independent variable are positive and have a range from 100-110. In this case, it would not be surprising if the regression line crossed the x-axis somewhere between x=0 and x=100 (i.e., from the first quadrant to the fourth quadrant), which would result in a negative value for the constant.The bottom line is that you need to have a good sense of your model and the variables within it, and a negative value on the constant should not generally be a cause for concern. Typically, it is the overall relationships between the variables that will be of the most importance in a linear regression model, not the value of the constant.
5 0
4 years ago
Which expressions are equivalent to this expression?
sashaice [31]
D & C are the correct answers.This is because of the Distributive Property.  

y+y+y +3z = 3y + 3z.

3(y+z) also gives you 3y + 3z. 

C is correct because everything adds up to 3y +3z:
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3 years ago
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