Answer:
25ft
Step-by-step explanation:
2hr=10ft
5hr=25ft
5-2=3 so you have to find what they did for the 3 hours which is another 2 plus half so 25ft.
Answer:
Step-by-step explanation:
perimeter of a rectangle = twice the length plus twice the width
P = 2L + 2W equation 1 P = 86 ft
Given the length is seven feet more than the width
L = W + 7 equation 2
Substitute equation 2 into equation 1
P = 2(W+7) + 2W = 86 ft
2W +14 + 2W = 86 ft
4W = 86 - 14
W = 72 / 4
W = 18 feet
There are an infinite number of solutions given the information you provided. For every real value of x there will be a corresponding real value of y.
y=5x+7 Has not restriction upon the domain or range...
What is the value of y? 5x+7
Hey ! there
Answer:
- <u>1</u><u>1</u><u>3</u><u>.</u><u>0</u><u>4</u><u> </u><u>unit </u><u>cube</u>
Step-by-step explanation:
In this question we are provided with a sphere <u>having</u><u> </u><u>radius </u><u>3 </u><u>units </u>and <u>value </u><u>of </u><u>π </u><u>is </u><u>3.</u><u>1</u><u>4</u><u> </u><u>.</u><u> </u>And we're asked to find the<u> </u><u>volume</u><u> of</u><u> </u><u>sphere</u><u> </u><u>.</u>
For finding volume of sphere , we need to know its formula . So ,

<u>Where</u><u> </u><u>,</u>
- π refers to <u>3.</u><u>1</u><u>4</u>
- r refers to <u>radius</u><u> of</u><u> sphere</u>
<u>Sol</u><u>u</u><u>tion </u><u>:</u><u> </u><u>-</u>
Now , we are substituting value of π and radius in the formula ,

Simplifying it ,

Cancelling 3 with 3 :

We get ,

Multiplying 4 and 3.14 :

Multiplying 12.56 and 9 :

- <u>Henceforth</u><u> </u><u>,</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>sphere</u><u> </u><u>having </u><u>radius </u><u>3 </u><u>units </u><u>is </u><em><u>1</u></em><em><u>1</u></em><em><u>3</u></em><em><u> </u></em><em><u>.</u></em><em><u>0</u></em><em><u>4</u></em><em><u> </u></em><em><u>units </u></em><em><u>cube </u></em><em><u>.</u></em>
<h2>
<u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
(13,infinity] hope this helps