The height is 15 feet.
0.5xbxh<_120 (equate formula for area of triangle to 120)
0.5x16xh<_120
16xh<_240 (120 divided by 0.5)
h<_15 (240 divided by 16)
<span>x = 4
Given the description of the triangles, you have 2 similar right triangles. The smaller triangle has a height of 20 and a base of 3x, while the larger has a height of (20+8) = 28 and a base of 4x + 2. We wish to determine the value of x. Since the triangles are similar, the ratio of corresponding sides will be a constant. So:
20/28 = (3x)/(4x+2)
(4x+2)20/28 = (3x)
(20/28)*4x+(20/28)*2 = (3x)
(80/28)*x+(40/28) = (3x)
(20/7)*x + 4/7 = 3x
4/7 = 3x - (20/7)*x
4/7 = (21/7)x - (20/7)*x
4/7 = x/7
4 = x
So the value of x is 4.</span>
Answer:
it is true.
Step-by-step explanation:
the proportions 4:6 and 10:15 can both be simplified into 2/3.
hope this helped! :)
Given:
The expression is:

To find:
The integration of the given expression.
Solution:
We need to find the integration of
.
Let us consider,

![[\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]](https://tex.z-dn.net/?f=%5B%5Cbecause%201%2B%5Ccos%202x%3D2%5Ccos%5E2x%2C1-%5Ccos%202x%3D2%5Csin%5E2x%5D)

![\left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Ctan%20%5Ctheta%20%3D%5Cdfrac%7B%5Csin%20%5Ctheta%7D%7B%5Ccos%20%5Ctheta%7D%5Cright%5D)
It can be written as:
![[\because 1+\tan^2 \theta =\sec^2 \theta]](https://tex.z-dn.net/?f=%5B%5Cbecause%201%2B%5Ctan%5E2%20%5Ctheta%20%3D%5Csec%5E2%20%5Ctheta%5D)


Therefore, the integration of
is
.