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alexira [117]
3 years ago
10

Saul decides to use the IQR to measure the spread of the data. Saul calculates the IQR of the data set to be 27.

Mathematics
1 answer:
padilas [110]3 years ago
3 0

Answer:

78

Step-by-step explanation:

The IQR is quartile 3 - quartile 1. First, we need to find the mean of the dataset, which is 50 -- the fifth number. Then, the median of the dataset on the left of the fifth number is the first quartile, and the median of the dataset on the right is the third. We get Q1 to then be halfway between 30 and 50, or 40, and Q3 to be halfway between 56 and n, so Q3 = (56+n)/2. Since we need Q3-Q1=27, or (56+n)/2-40=27, we have (56+n)/2=67 and 56+n=134, so n = 134-56=78

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5 0
2 years ago
What is the final amount if 893 is decreased by 2% followed by a further 7% decrease?
Ahat [919]

Answer 62 because if you work it out it wi give it

6 0
3 years ago
Which unit of measurement would be appropriate for the volume of a sphere with a radius of 2 meters
Semenov [28]
The volume of a sphere is found with the following formula:

V = \frac{4}{3}\pi r^3

The radius is raised to a power of 3. Since the radius is 2 <em>meters</em>, this means that the volume would be measured in cubic meters.
3 0
3 years ago
Yolanda is planning to put a pool in her backyard. The scaled model below gives the reduced measures for diameter and depth. Not
VMariaS [17]
Correct Answer: 
C option: 6 feet

Solution:
Since <span>Yolanda wants to keep the pool in proportion to the model, the ratio of diameter to depth of model and the pool will be same.

Let the depth of pool is x feet. So we can write:

Ratio of Diameter to Depth of Model = Ratio of Diameter to Depth of pool
</span>18:4=27:x \\  \\ &#10; \frac{18}{4} = \frac{27}{x} \\  \\ &#10;x=27* \frac{4}{18}  \\  \\ &#10;x=6
<span>
This means the depth of pool should be 6 feet if </span><span>Yolanda wants to keep the pool in proportion to the model.</span>
7 0
3 years ago
Read 3 more answers
What is the difference in volume between a sphere with radius r and a sphere with radius 0.3r?
REY [17]
The volume of the sphere of radius r is:
 V1 = (4/3) * (pi) * (r ^ 3)
 Where,
 r: sphere radius:
 The volume of the sphere of radius 0.3r is:
 V2 = (4/3) * (pi) * ((0.3r) ^ 3)
 Rewriting:
 V2 = (4/3) * (pi) * (0.027 (r) ^ 3)
 V2 = 0.027 (4/3) * (pi) * (r ^ 3)
 V2 = 0.027V1
 The difference is:
 V1-V2 = V1-0.027V1 = V1 (1-0.027)
 V1-V2 = 0.973 * (4/3) * (pi) * (r ^ 3)
 Answer:
 
the difference in volume between a sphere with radius and a sphere with radius 0.3r is:
 
V1-V2 = 0.973 * (4/3) * (pi) * (r ^ 3)
8 0
3 years ago
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