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4 years ago

According to the synthetic division below, which of the following statements are true

Mathematics

1 answer:

Hunter-Best [27]4 years ago

7 0

Answer:

B and D

Step-by-step explanation:

The polynomial x² + 6x - 8 ( from values in first row )

is being evaluated at x = - 5 thus the factor is (x + 5)

If (x + 5) is a factor the remainder = 0

Hence (x + 5) is not a factor since remainder = 12 ≠ 0

When the polynomial is evaluated at x = 5 it's value is 12

The remainder theorem states that f(h) = remainder, hence

f(- 5) = 12 ← remainder

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What is the volume of the figure?

FromTheMoon [43]

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4 years ago

Identify The degree of each monomial

vesna_86 [32]

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3 years ago

A computer manufacturing company has sent a mail survey to 2,800 of its randomly selected customers that have purchased a new la

vodka [1.7K]

Answer:

The 96% confidence interval for the population proportion of customers satisfied with their new computer is (0.77, 0.83).

Step-by-step explanation:

We have to calculate a 96% confidence interval for the proportion.

We consider the sample size to be the customers that responded the survey (n=800), as we can not assume the answer for the ones that did not answer.

The sample proportion is p=0.8.

$p=X/n=640/800=0.8$

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.8*0.2}{800}}\\\\\\ \sigma_p=\sqrt{0.0002}=0.014$

The critical z-value for a 96% confidence interval is z=2.054.

The margin of error (MOE) can be calculated as:

$MOE=z\cdot \sigma_p=2.054 \cdot 0.014=0.03$

Then, the lower and upper bounds of the confidence interval are:

$LL=p-z \cdot \sigma_p = 0.8-0.03=0.77\\\\UL=p+z \cdot \sigma_p = 0.8+0.03=0.83$

The 96% confidence interval for the population proportion is (0.77, 0.83).

4 0

3 years ago

Mrs. Valdez wanted to determine the number of people, p, she could safely take in her car to the fun run. She determined that p

dangina [55]

Answer:

She can take 2 people cause it’s less than 5

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Given an acceleration vector, initial velocity u0,v0,w0 , and initial position x0,y0,z0 , find the velocity and position vectors

dsp73

Answer:

Thus we find that velocity vector at time t is

(5t+15, 5t^2/2, 4t^2)

Step-by-step explanation:

given that acceleration vector is a funciton of time and at time t

$a(t) = (5,5t, 8t)$

v(t) can be obtained by integrating a(t)

v(t) = $(5t, 5t^2/2, 4t^2)+(u_0,v_0,w_0)\\=(5t+15, 5t^2/2, 4t^2)$

Thus we use the fact that acceleration is derivative of velocity and velocity is antiderivative of acceleration.

The arbitary constant normally used for integration C is here C vector = initial velocity (u0,v0,w0)

Position vector can be obtained by integrating v(t)

Thus we find that velocity vector at time t is

(5t+15, 5t^2/2, 4t^2)

5 0

3 years ago