Question

There are 42 chocolates in a​ box, all identically shaped. There 13 are filled with​ nuts, 15 with​ caramel, and 14 are solid chocolate. Someone randomly selects one​ piece, eats​ it, and then selects a second piece. Find the probability of selecting 2 nut candies. Express your answer as a simplified fraction.

Answer 1

Answer: The required probability is $\dfrac{169}{1764}$

Step-by-step explanation:

Since we have given that

Number of chocolates = 42

Number of chocolates filled with nuts = 13

Number of chocolates filled with caramel = 15

Number of chocolates filled with solid chocolate = 14

Probability of selecting 2 nut candies would be

$(\dfrac{13}{42})^2\\\\=\dfrac{169}{1764}$

Hence, the required probability is $\dfrac{169}{1764}$