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goldfiish [28.3K]
3 years ago
6

There are 42 chocolates in a​ box, all identically shaped. There 13 are filled with​ nuts, 15 with​ caramel, and 14 are solid ch

ocolate. Someone randomly selects one​ piece, eats​ it, and then selects a second piece. Find the probability of selecting 2 nut candies. Express your answer as a simplified fraction.
Mathematics
1 answer:
kvasek [131]3 years ago
6 0

Answer: The required probability is \dfrac{169}{1764}

Step-by-step explanation:

Since we have given that

Number of chocolates = 42

Number of chocolates filled with nuts = 13

Number of chocolates filled with caramel = 15

Number of chocolates filled with solid chocolate = 14

Probability of selecting 2 nut candies would be

(\dfrac{13}{42})^2\\\\=\dfrac{169}{1764}

Hence, the required probability is \dfrac{169}{1764}

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<h3>What is a percentage?</h3>

The percentage is calculated by dividing the required value by the total value and multiplying by 100.

Example:

Required percentage value = a

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Percentage = a/b x 100

Let the volume of 60% pure antifreeze be used to make 20% pure antifreeze.

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The volume of 20% pure antifreeze = 180 gallons

For 60% pure antifreeze:

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Applying,

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The volume of premium antifreeze to be used is 60 gallons.

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