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shtirl [24]
3 years ago
15

A student visiting the Sears Tower Skydeck is 1353 feet above the ground. Find the distance the student can see to the horizon.

Use the formula to approximate the distance d in miles to the horizon when h is the height of the viewer’s eyes above the ground in feet. Round to the nearest mile. A. 45 miles B. 601 miles C. 36 miles D. 1010 Miles

Mathematics
2 answers:
Anna007 [38]3 years ago
5 0

Answer:

Option A. 45 miles

Step-by-step explanation:

A student visiting the Sears Tower Skydeck is 1353 feet or 0.25625 miles above the ground.

We have to find the distance the student can see to the horizon.

We can see in the figure attached r is the radius of the earth.

h is the height of the tower and x is the distance to the horizon.

Now we can calculate the distance x by applying Pythagoras theorem in right angle ΔTOH. (Radius of the earth OH ⊥ tangent distance to the horizon TH)

(h + r)² = r² + x²

By putting the values in the formula

h = height of the tower = 0.25625 miles

r = radius of the earth = 3958.8 miles

(3958.8 + 0.25625)²= x² + (3958.8)²

x² = (3959.05)² - (3958.80)²

x² = 15674126.40 - 15672097.40

x² = 2029

x = √2029

x = 45.04 ≈ miles.

Therefore Option A. 45 miles is the answer.

kumpel [21]3 years ago
4 0
601 miles ok cause it goes from the area by "A=BxH or A=BH
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Answer:

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Step-by-step explanation:

A composite function can be written as g(h(x)), where h and g are basic functions.

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The inner function is the part we evaluate first. Frequently, we can identify the correct expression because it will appear within a grouping symbol one or more times in our composed function.

Here, we have 4x^2+8 inside parentheses. So h(x)=4x^2 + 8 is the inner function and the outer function is g(x)=3x^5.

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\frac{d}{dx}[f(g(x))]=f'(g(x))g'(x)

It tells us how to differentiate composite functions.

The function f(x)=3(4x^2+8)^5 is the composition, g(h(x)), of

     outside function: g(x)=3x^5

     inside function: h(x)=4x^2 + 8

The derivative of this is computed as

\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=3\frac{d}{dx}\left(\left(4x^2+8\right)^5\right)\\\\\mathrm{Apply\:the\:chain\:rule}:\quad \frac{df\left(u\right)}{dx}=\frac{df}{du}\cdot \frac{du}{dx}\\f=u^5,\:\:u=\left(4x^2+8\right)\\\\3\frac{d}{du}\left(u^5\right)\frac{d}{dx}\left(4x^2+8\right)\\\\3\cdot \:5\left(4x^2+8\right)^4\cdot \:8x\\\\120x\left(4x^2+8\right)^4

The derivative of the function is \frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4.

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Let z denote a variable that has a standard normal distribution. Determine the value z* to satisfy the following conditions. (Ro
Gre4nikov [31]

Answer:

a) z* = -1.97

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e) z* = 2.33

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Step-by-step explanation:

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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

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We have to look at the ztable, and find z which has a pvalue of 0.0244. So it is z* = -1.97

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This is z which has a pvalue of 0.201/2 = 0.1055. So it is z* = -1.25.

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3 years ago
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