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ryzh [129]
3 years ago
5

If a dozen eggs cost $1.35,what is the unit cost?

Mathematics
2 answers:
Lemur [1.5K]3 years ago
8 0

Answer:

The cost of an egg is $0.11

Step-by-step explanation:

Given : The cost of one dozen of eggs is $ 1.35

We have to find the cost of one egg.

We know, one dozen has 12 units

Thus, One dozen of eggs contain 12 eggs

So cost of 12 eggs is $ 1.35

So to find the cost of one egg divide the cost by 12.

We get,

1 egg = \frac{1.35}{12}=0.1125

Thus, The cost of an egg is $0.11

Semmy [17]3 years ago
8 0
1.35/ 12 = 0,112 So the unit cost will be 0,112 Check the answer 0,112 *12 = 1.35 You got it my friend
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Complete the following statement.
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Sin C = AB / AC
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Lucy is knitting a blanket and needs to buy some more yarn. at her local craft store, 2 skeins of yarn cost $7 and 8 skeins of y
laila [671]

Answer:

4

Step-by-step explanation:

Proportionality between skein values

8:2=4:1

Proportionality between cost values

28:7=4:1

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7 0
2 years ago
Which explanation about figures is correct? * A. All rhombuses are parallelograms. Parallelograms have 2 pairs of parallel sides
bezimeni [28]

Answer:

The correct option is;

A. All rhombuses are parallelograms. Parallelograms have 2 pairs of parallel sides. Therefore, all rhombuses have 2 pairs of parallel sides

Step-by-step explanation:

A rhombus is a quadrilateral that has all 4 sides, it has equal opposite angles and perpendicular diagonals that bisect one another  as well as having a pair of opposite parallel sides making it a parallelogram

A rhombus is similar to a parallelogram which also has equal opposite and parallel sided and equal opposite angles and the diagonals of a parallelogram also bisect each other.

4 0
3 years ago
The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width
blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given  perimeter

perimeter of rectangle = 2 ( length +  width )

=> 30.8 km = 2 ( x + y )  

=>x + y = \frac{30.8}{2}

=> y = 15.4 – x             ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,  

=> length^2 + width^2 = diagonal^2

=> x^2 + y^2 = 11^2

=> x^2 + y^2 = 121

On substituting value of y from (1) in above equation we get

=> x^2 + (15.4-x)^2 = 121

=>x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x   = 121

=> 2x^2-30.8x + 237.16 -121  = 0

=> 2x^2-30.8x + 116.16 = 0

Solving above quadratic equation using quadratic formula

General form of quadratic equation is  

ax^2 +bx +c = 0

And quadratic formula for getting roots of quadratic equation is  

x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}

As equation is 2x^2-30.8x + 116.16 = 0, in our case

a = 2 ,  b = -30.8 and c = 116.16

Calculating roots of the equation we get

x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}

x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{(30.8\pm29.33)}4

x=\frac{(30.8+29.33)}{4}

x=\frac{(30.8-29.33)}{4}

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,  

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0
3 years ago
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