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ryzh [129]
3 years ago
5

If a dozen eggs cost $1.35,what is the unit cost?

Mathematics
2 answers:
Lemur [1.5K]3 years ago
8 0

Answer:

The cost of an egg is $0.11

Step-by-step explanation:

Given : The cost of one dozen of eggs is $ 1.35

We have to find the cost of one egg.

We know, one dozen has 12 units

Thus, One dozen of eggs contain 12 eggs

So cost of 12 eggs is $ 1.35

So to find the cost of one egg divide the cost by 12.

We get,

1 egg = \frac{1.35}{12}=0.1125

Thus, The cost of an egg is $0.11

Semmy [17]3 years ago
8 0
1.35/ 12 = 0,112 So the unit cost will be 0,112 Check the answer 0,112 *12 = 1.35 You got it my friend
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8,431.62709 which digit is in the ten-thousand place?
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6 is in the ten thousand place
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What is the surface area of the pyramid <br> 224ft<br> 460ft <br> 112 ft<br> 336ft
marusya05 [52]

Use the formula

S=wh+lw+ls+lp

And you should get your answer.

1.)label the shape with length width side and p then multiply the letters that are together in the formula.then add whatever you got when you multiples tougher and that's ur answer

4 0
3 years ago
Solve for m and n<br> I been stuck on this question for an hour
Crazy boy [7]

Answer:

m = 10 , n = 5\sqrt{2}

Step-by-step explanation:

using the cosine and tangent ratio in the right triangle and the exact values

cos45° = \frac{1}{\sqrt{2} } and tan45° = 1 , then

cos45° = \frac{adjacent}{hypotenuse} = \frac{5\sqrt{2} }{m} = \frac{1}{\sqrt{2} } ( cross- multiply )

m = 5\sqrt{2} × \sqrt{2} = 5 × 2 = 10

-----------------------------------------

tan45° = \frac{opposite}{adjacent} = \frac{n}{5\sqrt{2} } = 1 , then

n = 5\sqrt{2}

3 0
2 years ago
I need help with my math homework. The questions is: Find all solutions of the equation in the interval [0,2π).
Aleksandr-060686 [28]

Answer:

\frac{7\pi}{24} and \frac{31\pi}{24}

Step-by-step explanation:

\sqrt{3} \tan(x-\frac{\pi}{8})-1=0

Let's first isolate the trig function.

Add 1 one on both sides:

\sqrt{3} \tan(x-\frac{\pi}{8})=1

Divide both sides by \sqrt{3}:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}

Now recall \tan(u)=\frac{\sin(u)}{\cos(u)}.

\frac{1}{\sqrt{3}}=\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}

or

\frac{1}{\sqrt{3}}=\frac{-\frac{1}{2}}{-\frac{\sqrt{3}}{2}}

The first ratio I have can be found using \frac{\pi}{6} in the first rotation of the unit circle.

The second ratio I have can be found using \frac{7\pi}{6} you can see this is on the same line as the \frac{\pi}{6} so you could write \frac{7\pi}{6} as \frac{\pi}{6}+\pi.

So this means the following:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}

is true when x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi

where n is integer.

Integers are the set containing {..,-3,-2,-1,0,1,2,3,...}.

So now we have a linear equation to solve:

x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi

Add \frac{\pi}{8} on both sides:

x=\frac{\pi}{6}+\frac{\pi}{8}+n \pi

Find common denominator between the first two terms on the right.

That is 24.

x=\frac{4\pi}{24}+\frac{3\pi}{24}+n \pi

x=\frac{7\pi}{24}+n \pi (So this is for all the solutions.)

Now I just notice that it said find all the solutions in the interval [0,2\pi).

So if \sqrt{3} \tan(x-\frac{\pi}{8})-1=0 and we let u=x-\frac{\pi}{8}, then solving for x gives us:

u+\frac{\pi}{8}=x ( I just added \frac{\pi}{8} on both sides.)

So recall 0\le x.

Then 0 \le u+\frac{\pi}{8}.

Subtract \frac{\pi}{8} on both sides:

-\frac{\pi}{8}\le u

Simplify:

-\frac{\pi}{8}\le u

-\frac{\pi}{8}\le u

So we want to find solutions to:

\tan(u)=\frac{1}{\sqrt{3}} with the condition:

-\frac{\pi}{8}\le u

That's just at \frac{\pi}{6} and \frac{7\pi}{6}

So now adding \frac{\pi}{8} to both gives us the solutions to:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}} in the interval:

0\le x.

The solutions we are looking for are:

\frac{\pi}{6}+\frac{\pi}{8} and \frac{7\pi}{6}+\frac{\pi}{8}

Let's simplifying:

(\frac{1}{6}+\frac{1}{8})\pi and (\frac{7}{6}+\frac{1}{8})\pi

\frac{7}{24}\pi and \frac{31}{24}\pi

\frac{7\pi}{24} and \frac{31\pi}{24}

5 0
3 years ago
GUYS HELP I GOT TOO MUCH TO DO CAN YOU DO ME A SOLID
MrRissso [65]

Answer:

2 radical 13

Step-by-step explanation:

3 0
2 years ago
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