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3 years ago

Two parents who are both GG for a gene are crossed. what is the genetic makeup of the offspring.

Chemistry

2 answers:

snow_lady [41]3 years ago

7 0

<u>Answer:</u> The correct answer is Option C.

<u>Explanation:</u>

An offspring gets the gene which is formed by the intermixing of the two parents.

It is given that the two parents have the same gene which is "GG". As, we can see there is no dominant trait in the parents gene.

Hence, the offspring will also inherit the same gene type which is "GG".

Therefore, the correct answer is option C.

nexus9112 [7]3 years ago

5 0

The option would be C, as there is no way for a recessive gene to happen, if both parents are dominant.

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The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute the ratio of the reaction rate constants for these two reactions at 25°C.

$\frac{K_1}{K_2}=?$

Activation energy of the reaction 1 , $Ea_1$ = 14.0 kJ/mol

Activation energy of the reaction 2, $Ea_1$ = 11.9 kJ/mol

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According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

The expression used with catalyst and without catalyst is,

$\frac{K_2}{K_1}=\frac{A\times e^{\frac{-Ea_2}{RT}}}{A\times e^{\frac{-Ea_1}{RT}}}$

$\frac{K_2}{K_1}=e^{\frac{Ea_1-Ea_2}{RT}}$

where,

$K_2$ = rate constant reaction -1

$K_1$ = rate constant reaction -2

Activation energy of the reaction 1 , $Ea_1$ = 14.0 kJ/mol = 14,000 J

Activation energy of the reaction 2, $Ea_1$ = 11.9 kJ/mol = 11,900 J

R = gas constant = 8.314 J/ mol K

T = temperature = $25^oC=273+25=298 K$

Now put all the given values in this formula, we get

$\frac{K_1}{K_2}=e^{\frac{11,900- 14,000Jl}{8.314 J/mol K\times 298 K}}=2.3340$

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