Explanation:
The given data is as follows.
, 
= 2257 kJ/kg, 
= ?
For water, 
= 4.184 
Formula to calculate heat of vaporization is as follows.
= 
Hence, putting the values into the above formula as follows.
=
= 
= 2257 kJ/kg - 376.56 kJ/kg
= 1880.44 kJ/kg
Thus, we can conclude that enthalpy of liquid water at 
is 1880.44 kJ/kg.
2.79 mol of MnSiO3
This will be very close but may not be exactly accurate, depending on what your periodic table says.
The answer for the question above is A. the gravitational pull of the moon on the water near the coast. The sun and and the moon are responsible for the rising and falling of the ocean tides. The gravitational pull of the moon and the sun makes the water in the oceans bulge, causing a continuous change between high and low tide.
This separation technique is a 4-step procedure. First, add H₂SO₄ to the solution. Because of common ion effect, BaSO₄ will not react, only Mg(OH)₂.
Mg(OH)₂ + H₂SO₄ → MgSO₄ + 2 H₂O
The aqueous solution will now contain MgSO₄ and BaSO₄. Unlike BaSO₄, MgSO₄ is soluble in water. So, you filter out the solution. You can set aside the BaSO₄ on the filter paper. To retrieve Mg(OH)₂, add NaOH.
MgSO₄ + 2 NaOH = Mg(OH)₂ + Na₂SO₄
Na₂SO₄ is soluble in water, while Mg(OH)₂ is not. Filter this solution again. The Mg(OH)₂ is retrieved in solid form on the filter paper.
Personal experience from Ag Mech classes-Concrete cools faster than metal.
