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Rom4ik [11]
2 years ago
9

RESEARCHING ENERGY TRANSFORMATIONS

Chemistry
1 answer:
geniusboy [140]2 years ago
5 0

Answer:

Two types of technology and the energy transformation that occurs within those types of technology  that make them work is described below in detail.

Explanation:

A drone, in technological courses, is an unmanned aircraft. ... Typically, a drone is a hovering automaton that can be remotely commanded or cruise autonomously through software-managed flight systems in their installed systems, working in combination with onboard sensors and GPS.

Laptops consolidate all the input/output parts and abilities of a desktop processor, including the presentation screen, tiny speakers, a keyboard, a data storehouse device, sometimes an optical disc drive, aiming devices, with a running system, a processor, and memory into a particular unit.

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A student mixed some yellow sulfur powder with some iron filings. She was able to take the iron out of the sulfur by using a mag
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Physical change is a change in which there is no rearrangement of atoms and thus no new substance is formed. There is only change in physical state of the substance. The change can be reversed using physical methods.

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Common additives to drinking water include elemental chlorine, chloride ions, and phosphate ions. Recently, reports of elevated
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A 10.0 mL sample of 0.25 M NaOH(aq) is titrated with 0.10 M HCl(aq) (adding HCl to NaOH). Determine which region on the titratio
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Answer:

1) After adding 15.0 mL of the HCl solution, the mixture is before the equivalence point on the titration curve.

2) The pH of the solution after adding HCl is 12.6

Explanation:

10.0 mL of 0.25 M NaOH(aq) react with 15.0 mL of 0.10 M HCl(aq). Let's calculate the moles of each reactant.

nNaOH=\frac{0.25mol}{L} .10.0 \times 10^{-3} L=2.5 \times 10^{-3}mol

nHCl=\frac{0.10mol}{L} \times 15.0 \times 10^{-3} L=1.5 \times 10^{-3}mol

There is an excess of NaOH so the mixture is before the equivalence point. When HCl completely reacts, we can calculate the moles in excess of NaOH.

                    NaOH       +       HCl       ⇒       NaCl      +         H₂O

Initial          2.5 × 10⁻³         1.5 × 10⁻³               0                      0

Reaction    -1.5 × 10⁻³        -1.5 × 10⁻³          1.5 × 10⁻³          1.5 × 10⁻³

Final            1.0 × 10⁻³               0                 1.5 × 10⁻³          1.5 × 10⁻³

The concentration of NaOH is:

[NaOH]=\frac{1.0 \times 10^{-3} mol }{25.0 \times 10^{-3} L} =0.040M

NaOH is a strong base so [OH⁻] = [NaOH].

Finally, we can calculate pOH and pH.

pOH = -log [OH⁻] = -log 0.040 = 1.4

pH = 14 - pOH = 14 - 1.4 = 12.6

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3 years ago
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