The force will remain same if the mass of each sphere is doubled and the distance between them is doubled as well.
The force of gravitation between two spheres is given by
![f=\frac{G m1 m2}{r^{2}}](https://tex.z-dn.net/?f=%20f%3D%5Cfrac%7BG%20m1%20m2%7D%7Br%5E%7B2%7D%7D%20%20%20)
m1= mass of first object
m2= mass of second object
r= distance between the masses
Now if each mass is doubled and the distance r is doubled as well
![F'= \frac{G (2m1)(2m2)}{(2r)^{2}}](https://tex.z-dn.net/?f=%20F%27%3D%20%5Cfrac%7BG%20%282m1%29%282m2%29%7D%7B%282r%29%5E%7B2%7D%7D%20%20%20)
![F'= \frac{4 G m1 m2}{4r^{2}}](https://tex.z-dn.net/?f=%20F%27%3D%20%5Cfrac%7B4%20G%20m1%20m2%7D%7B4r%5E%7B2%7D%7D%20%20%20)
F'=![\frac{G m1 m2 }{r^{2}}](https://tex.z-dn.net/?f=%20%5Cfrac%7BG%20m1%20m2%20%7D%7Br%5E%7B2%7D%7D%20%20%20)
so F'= F
so the force remains same and is equal to 1000 N.
Player #2 has the most momentum. Think it as if you are rolling a baseball, bowling ball, and softball down a hill. it will take more effort to stop the bowling ball, because it has more momentum.
0.32 km
How to reach the answer:
The formula below provides the tsunami's speed in response to the query.
s = 356√d
when the tsunami's speed is 200 km/h, the equation's "s" is changed to "200," and the equation of speed is then expressed as follows.
200 = 356√d
The equation can be changed to compute the depth of the water as,
√d = 200÷356
√d = 0.562
Now on squaring both sides:
(√d)² = (0.562)²
d = (0.562)² = 0.316 or 0.32
Therefore the approximate depth of water for a tsunami travelling at 200km/h is 0.32 km
Know more about speed here:
brainly.com/question/19930939
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The correct answer that would best complete the given statement above would be the last option: COLDER. Climates on Earth get colder <span>as you move from the equator to the poles. The places that are located near or on the equator experience the warmest or the hottest climates such as Africa. Hope this answer helps. </span>
Answer:
α = ![21.6 rad/s^2](https://tex.z-dn.net/?f=%2021.6%20rad%2Fs%5E2%20)
Explanation:
Applying the equations of motion to determine angular acceleration of the unit,
The sum of moments about O is equal to the product of angular acceleration and moment of inertia
∑Mo = Io*α
Taking the anticlockwise direction as positive moment,
= ( -(1150) + (1400) ) * (0.5 / 2) + ( (475) - (650) ) * (0.3 / 2) - F = Io*α
= 36.5 - (2.5 N.m) =
*α
NOTE: moment of inertia of the pulleys in this instance = ![(m*ko^2)](https://tex.z-dn.net/?f=%20%28m%2Ako%5E2%29%20)
Hence, 33.75 =
* α
Solving, α = ![21.6 rad/s^2](https://tex.z-dn.net/?f=%2021.6%20rad%2Fs%5E2%20)