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Ksivusya [100]
3 years ago
15

How much heat is released when 35kg of water freezes?

Physics
1 answer:
inn [45]3 years ago
3 0
You need an additional point of data here: the enthalpy of fusion, or conversely the enthalpy of melting (they differ only by their sign). For water (or ice) that value is gotten from sources such as the internet

<span>ΔH°(fus) = 6.01 kJ/mole </span>

<span>Since you have 35 000g, how many moles do you have? </span>
<span>Moles H2O = 35000 g/(18.015 g/mole) = 1942.8 moles</span>

<span>So, take that ΔH°(fus) in kJ/mole, multiply by the number of moles, and there ya go! 
</span>
6.01 x 1942.8 = 11,676 kJ of energy is released

Hope I helped!! xx
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Two sticky spheres are suspended from light ropes of length LL that are attached to the ceiling at a common point. Sphere AA has
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Answer:

  h’ = 1/9 h

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This exercise must be solved in parts:

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final point. Lower, just before the crash

         Em_f = K = ½ m v_{b}^2

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* Now let's analyze the collision of the two spheres. We form a system formed by the two spheres, therefore the forces during the collision are internal and the moment is conserved

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final instant. Right after the crash

         p_f = (2m + m) v

       

the moment is preserved

         p₀ = p_f

         m v_b = 3m v

         v = v_b / 3

         

          v = ⅓ \sqrt{2gh}

* finally we analyze the movement after the crash. Let's use the conservation of energy to the system formed by the two spheres stuck together

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          Em₀ = K = ½ 3m v²

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          Em₀ = Em_f

          ½ 3m v² = 3m g h’

           

we substitute

         h’=  \frac{v^2}{2g}

         h’ =  \frac{1}{3^2} \  \frac{ 2gh}{2g}

         h’ = 1/9 h

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