Answer: x = −18
Step-by-step explanation:
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-4' to each side of the equation.
4 + -4 + -1x = 22 + -4
Combine like terms: 4 + -4 = 0
0 + -1x = 22 + -4
-1x = 22 + -4
Combine like terms: 22 + -4 = 18
-1x = 18
Divide each side by '-1'.
x = -18
Simplifying
x = -18
Its c 10 and other fillar so i can answer
The sequence can be represented by
, where
is a whole number(
and
is an integer). By this, we should be able to plug in some whole number x and be able to get these values if they are in the sequence. To test this, let's set these numbers equal to
and confirm that there is a whole number x which equals the values selected.



When trying 160 with our equation, we find that x doesn't equal a whole number, thus our answer is C, or 160. To confirm our answer, we can test 170 and 210 and confirm that they both give us a value for x which is a whole number.


Answer:
The number is 492,875.
Step-by-step explanation:
Given:
A number that is = 
Place value of 4 = 
Place value is ten thousands.
We have to identify the number where the place value of 4 is 10 times of the given number.
Numbers given:
284,796 or 327,498 or 492,875 and 742,186.
Lets see the place value of 4 in each of the number.
⇒
-
place value of
is
. - Place value of 4 is thousands.
⇒
place value of
is
.- Place value of 4 is hundreds.
⇒
place value of
is
.- Place value of 4 is hundred thousands.
⇒
place value of
is
.- Place value of 4 is ten thousands.
Notes:
Ten thousands multiplied with ten is hundreds thousand.
⇒ 
So,
The number which has digit 4 as hundred thousands place values is 492,875.
Answer:
a) 6 mins
b) 70km/h
c) t= 45
Step-by-step explanation:
a) The bus stops from t=10 to t=16 minutes since the distance the busvtravelled remained constant at 15km
Duration
= 16 -10
= 6 minutes
b) Average speed
= total distance ÷ total time
Total time
= 24min
= (24÷60) hr
= 0.4 h
Average speed
= 28 ÷0.4
= 70 km/h
c) Average speed= total distance/ total time
Average speed
= 80km/h
= (80÷60) km/min
= 1⅓ km/min
1⅓= 28 ÷(t -24)
<em>since</em><em> </em><em>duration</em><em> </em><em>for</em><em> </em><em>return</em><em> </em><em>journey</em><em> </em><em>is</em><em> </em><em>from</em><em> </em><em>t</em><em>=</em><em>2</em><em>4</em><em> </em><em>mins</em><em> </em><em>to</em><em> </em><em>t</em><em> </em><em>mins</em><em>.</em>
(t -24)= 28
t - 32= 28
t= 32 +28
t= 60
t= 
t= 45
*Here, I assume that this is a displacement- time graph, so the distance shown is the distance of the bus from the starting point because technically if it is a distance-time graph, the distance would still increase as the bus travels the 'return journey'.
Thus, distance is decreasing after t=24 and reaches zero at time= t mins so that is the return journey. (because when the bus returns back to starting point, displacement/ distance from starting point= 0km)