The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]
<h3>How to determine the range of speed associate to desired gas mileages</h3>
In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:
g = 10 + 0.7 · v - 0.01 · v² (1)
An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].
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Answer:
BUTTHOLE IS A BUTT THAT FARTS POOP....YA
3*3+4*4=x*x and 9+16=25 so x is 5 and then add other sides so 5+8+4+5
There is 1000 grams in a kilogram so he had a mass of 5,000 grames in his bag
First, we start with the equation that the problem told us, which is:
R + 6 = 2 * (x + 6)
Then, we distribute the two:
R + 6 = 2x + 12
Now, we put R on its own side.
R = 2x +6
So, the answer must be C, 2x + 6