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Temka [501]
3 years ago
7

In february a little town received snow on a daily basis. The first day they had 10 inches, 3 inches the second, 7 inches the 3r

d, and 4 inches on the fourth day. What was the average snowfall?
Physics
2 answers:
Vitek1552 [10]3 years ago
8 0

Answer:

The average is 6

Explanation:

To find the average, you have to first add all the numbers. After you add all the numbers up, then you divide by how many numbers there are. This one had 4 numbers so you divide by 4

viktelen [127]3 years ago
5 0

Answer:

6

Explanation:

Add 10+7+3+4 and then divide your answer by 4

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Can someone please explain how to solve for impulse if momentum is not given, only mass and velocity are given
Marta_Voda [28]
You're in luck !  Momentum is the product of (mass) times (velocity). 

So if you're given mass and velocity, simply multiply them, and voila,
you have the momentum.
6 0
4 years ago
A railroad car of mass M moving at a speed v1 collides and couples with two coupled railroad cars, each of the same mass M and m
marshall27 [118]

Answer:

vf = v₁/3 + 2v₂/3

Explanation:

Using the law of conservation of linear momentum,

momentum before impact = momentum after impact

So, Mv₁ + 2Mv₂ = 3Mv (since the railroad cars combine) where v₁ = initial velocity of first railroad car, v₂ = initial velocity of the other two coupled railroad cars, and vf = final velocity of the three railroad cars after impact.

Mv₁ + 2Mv₂ = 3Mvf

dividing through by 3M, we have

v₁/3 + 2v₂/3 = vf

vf = v₁/3 + 2v₂/3

6 0
3 years ago
Ender and Shen are flying at each other during a battle in space. Ender moves with a velocity v1 of 12 m/s and Shen, with a mass
Shalnov [3]

Answer:

Ender's mass = 2.25 kg

Explanation:

using law of conservation of momentum .

since there is inelastic collision

given.

let \ \ m_{1} =  m \\m_{2} = 45 kg \\v_{1} = 12 m/s \\v_{2} = 9 m/s \\\\V_{3} =6.4 m/s\\using \  \ \\m_{1}v_{1} + m_{2}v_{2} = (m_{1} +m_{2})V\\m\times12 + 45\times9  = (m+45)\times6.4\\64m -12m        = 405 -288\\52m =117\\m =\frac{117}{52}\\m =2.25kg

6 0
3 years ago
Enumerar 5 actividades en casa o en el trabajo en la que usualmente se mantenga una postura corporal incorrecta
ludmilkaskok [199]

Answer:

Existen cinco actividades en las que se mantiene una postura corporal incorrecta:

1) Sentarse en una silla.

2) Agacharse y levantar una objeto del piso, especialmente cuando es pesado.

3) Sentarse en un escritorio, especialmente frente a una computadora.

4) Llevar una mochila, especialmente si está sobrecargada.

5) Dormir sobre una cama en una posición inadecuada.

Explanation:

Existen cinco actividades en las que se mantiene una postura corporal incorrecta:

1) Sentarse en una silla.

2) Agacharse y levantar una objeto del piso, especialmente cuando es pesado.

3) Sentarse en un escritorio, especialmente frente a una computadora.

4) Llevar una mochila, especialmente si está sobrecargada.

5) Dormir sobre una cama en una posición inadecuada.

5 0
3 years ago
What is the net force acting on a falling object when it reaches terminal velocity? a force equal to gravity 9.8 m/s2 two times
Leno4ka [110]

Answer:

The net force is zero

Explanation:

When an object is falling, there are two forces acting on it:

- The force of gravity, which is equal to the weight of the object, which pushes the object downwards

- The air resistance, which acts against the motion of the object, so it pulls upward

While the magnitude of the force of gravity is constant, the magnitude of the air resistance increases as the velocity of the falling object increases: at some point of the motion, the air resistance becomes equal in magnitude to the force of gravity. At this point, the net force on the object becomes zero, and according to Newton's second law, the acceleration of the object becomes also zero:

F=ma

But zero acceleration means that the velocity of the object is now constant: this is known as terminal velocity.

5 0
3 years ago
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