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Temka [501]
3 years ago
7

In february a little town received snow on a daily basis. The first day they had 10 inches, 3 inches the second, 7 inches the 3r

d, and 4 inches on the fourth day. What was the average snowfall?
Physics
2 answers:
Vitek1552 [10]3 years ago
8 0

Answer:

The average is 6

Explanation:

To find the average, you have to first add all the numbers. After you add all the numbers up, then you divide by how many numbers there are. This one had 4 numbers so you divide by 4

viktelen [127]3 years ago
5 0

Answer:

6

Explanation:

Add 10+7+3+4 and then divide your answer by 4

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A dvd drive has a maximum speed of 72000 revolutions per minute. if a dvd has a diamter of 12 what is the linear speed
Brilliant_brown [7]
The question isn't clear enough, I think it ask us to calculate the linear speed of a point at the edge of the DVD.
Now let's imagine we're a point at the edge of the DVD, we're undergoing a circular motion. Each minute we will complete a circular track 7200 times, now we need to know the distance we travel each turn. The perimeter of the DVD, a circular object is:
P=2\pi.R
Know recall that:
v=\frac{d}{t}
We now need to know how much distance is traveled during a minute or 60 seconds:
D=7200\times 2\pi\times R
Finally we divide this result with t=60 seconds:
v=\frac{7200\times2\pi\times R}{60}
\\
R=\frac{12}{2}=6

v\approx 4523.89 \frac{units}{second}
Where the distance units were named units as the length unit is not specified in this exercise.<span />
7 0
4 years ago
Joseph is sitting in the family van. His mother is driving him from their house to the library. Joseph waves as he passes his fr
zubka84 [21]
I think it is maria but i am more sure than wondering
4 0
3 years ago
How many justified by Bohr model?
Dominik [7]

X-ray formation

Energy difference in the first ionization of the same group of elements

Differential linear emission spectra of different elements

Explanation:

The formation of x-ray, energy difference in the first ionization of the same group of elements and differential linear emission spectra of different elements can be justified by the Bohr model of the atom.

  • According to Neil Bohr, in an atom, the extranuclear part consists of electrons in specific spherical orbits around the nucleus.
  • Bohr's model explained the discrete lines in atomic spectrum of different elements.
  • Due to excitation of electrons, some rays are given off. Some of these are energetic like x-rays.
  • The energy difference between the first ionization of the same group of elements is a proof that electrons are in specific spherical orbits.
  • The higher the energy the level, the ease at which electrons can be removed and the lower the ionization energy.

Learn more:

Bohr model of the atom brainly.com/question/4986277

#learnwithBrainly

3 0
4 years ago
The hour and minute hands of a tower clock like Big Ben in London are 2.79 m and 4.44 m long and have masses of 58.2 kg and 90 k
LuckyWell [14K]

Answer: 895.85 x 10^-6 J or 8.96 x 10^-4 J

Explanation:

Angular kinetic energy E in Joules

E = ½Iw^2

W is angular velocity in radians/sec

1 radian/sec = 9.55 rev/min

I is moment of inertia in kgm^2

I = cMR^2

M is mass (kg), R is radius (meters)

c = 1/3 for a rod around its end, R = length

For minute hand

I = (1/3)(90)(4.44)^2 = 0.33 x 90 x 19.7136 = 585.49

w= 1 rev/hour = 1 rev/3600sec = 2pi/ 3600 = pi/1800 rad/s

KE = 1/2(1/3)(90)(4.44)^2(pi/1800)^2 = 0.5 x 0.33 x 90 x 19.7136 x 3.05 x 10^-6

KE = 0.00089 J

For hour hand

I = (1/3)(58.2)(2.79)^2 = 0.33 x 58.2 x 2.79^2 = 149.5

w = 1 rev/12hour = 1 rev/(12x3600sec) = 2pi/ 12x3600 = pi/21600 rad/s

KE = 1/2(1/3)(90)(4.44)^2(pi/21600)^2 = 0.5 x 0.33 x 90 x 19.7136 x 2.12 x 10^-8

KE = 5.85 x 10^-6 J

Therefore total kinetic energy = 895.85 x 10^-6 J

4 0
4 years ago
A dolphin keeps up with a boat for a distance of 51 miles for 3 hours. What is the dolphin’s average speed?
Sedbober [7]

Answer:

The dolphin's speed is 17 mi/h

Explanation:

Use the formula for average velocity: Distance/time

then the average speed of the dolphin is 51/3  mi/h = 17 mi/h

7 0
4 years ago
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