All categories

3 years ago

you push a 51 kg box with a force of 485 N. the friction force on the box is 232 N. calculate the acceleration of the crate.

Physics

1 answer:

vichka [17]3 years ago

3 0

Answer:

a = 4.96 m/s²

Explanation:

Given,

The mass of the box, m = 51 Kg

The magnitude of the applied force, Fₐ = 485 N

The friction force on the box, Fₓ = 232 N

The net force acting on the box is,

F = Fₐ - Fₓ

Substituting the given values in the above equation

F = 485 - 232

= 253 N

The acceleration of the crate is given by

a = F/m

= 253 / 51

= 4.96 m/s²

Hence, the acceleration of the crate is, a = 4.96 m/s²

You might be interested in

two equal and unlike parallel forces of magnitude 34N act on a rigid body,such that the moment of couple is 8.50 Nm. calculate t

goldfiish [28.3K]

The moment of a couple is Force × perpendicular distance from the arm of the line of action

so the arm of the couple= moment of couple/force=8.5/34=0.25m

the arm is 0.25m

5 0

3 years ago

What kind of energy is stored when you squeeze a mattress?

yuradex [85]

Elastic Energy is stored in it.

4 0

3 years ago

Read 2 more answers

Two forces of magnitudes 4.0 Newtons and 3.0 Newtons pull on a box. The forces make an angle of 40° with each other. What is the

leonid [27]

Answer:

6.6 N

Explanation:

Let's take the direction of the force of 4.0 N as positive x-direction. This means that the force of 3.0 N is at 40 degrees above it. So the components of the two forces along the x- and y-directions are:

$F_{1x} = 4.0 N\\F_{1y} = 0$

$F_{2x} = 3.0 N cos 40^{\circ}=2.3 N\\F_{2y} = 3.0 N sin 40^{\circ} = 1.9 N$

So the resultant has components

$F_x = F_{1x}+F_{2x}=4.0 N +2.3 N = 6.3 N\\F_y = F_{1y} + F_{2y} = 0 + 1.9 N = 1.9 N$

So the magnitude of the resultant is

$F=\sqrt{F_x^2 +F_y^2}=\sqrt{(6.3)^2+(1.9)^2}=6.6 N$

And in order for the body to be balanced, the third force must be equal and opposite (in direction) to this force: so, the magnitude of the third force must be 6.6 N.

3 0

3 years ago

If you were on a ship at sea, and a tsunami passed under your ship, what would probably be your reaction? explain.

swat32

<span>Extremely powerful single waves have no effect on ships at sea since the depth of water allows the energy to be distributed over hundreds and thousands of feet. In deep water, the bigger the wave, the faster it moves and the slower the surface changes height. As the wave gets into shallow waters, it slows down and can start to pile up to large heights.</span>

6 0

3 years ago

The back wall of a home aquarium is a mirror that is a distance of 46.0 cm away from the front wall. The walls of the tank are n

monitta

Answer:

i know the questin but i got to try and find it

Explanation:

5 0

3 years ago