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Anit [1.1K]
3 years ago
14

you push a 51 kg box with a force of 485 N. the friction force on the box is 232 N. calculate the acceleration of the crate.

Physics
1 answer:
vichka [17]3 years ago
3 0

Answer:

a = 4.96 m/s²

Explanation:

Given,

The mass of the box, m = 51 Kg

The magnitude of the applied force, Fₐ = 485 N

The friction force on the box, Fₓ = 232 N

The net force acting on the box is,

                                 F = Fₐ - Fₓ

Substituting the given values in the above equation

                                  F = 485 - 232

                                    = 253 N

The acceleration of the crate is given by

                                   a = F/m

                                      = 253 / 51

                                      = 4.96 m/s²

Hence, the acceleration of the crate is, a = 4.96 m/s²

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<h3>What is the law of conservation of momentum?</h3>

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

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The energy that was lost due to air resistance while she was bouncing is determined as 3,360 J.

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