Ask question

Ask question

All categories

olga nikolaevna [1]

3 years ago

13

Joseph is sitting in the family van. His mother is driving him from their house to the library. Joseph waves as he passes his fr

iend Maria. Which of the following is not moving with respect to Joseph?
Maria
the family van
the library
Jane's house

1 answer:

zubka84 [21]3 years ago

4 0

I think it is maria but i am more sure than wondering

You might be interested in

Can angular displacement b both scalar and vector??

patriot [66]

<span>Finite angular displacements are not vector quantities, the reason being that they do not obey the law of vector addition. This law asserts that the order in which vectors are added does not affect their sum. However finite angles under addition tend towards commutivity as the angles become very small. Infinitesimal angles do commute under addition, making it possible to treat them as vectors.</span>

6 0

3 years ago

What is the distance traveled by a vehicle in 12 minutes, if it’s speed is 35 km/h

Artemon [7]

Answer:

7 km

Explanation:

Okay so an hour is 60 mins, so

60/ 12 = 5

35/ 5 = 7

7 km

5 0

3 years ago

Read 2 more answers

A rubber band has a spring constant of 75 N/m. How much force is required to stretch the rubber band 0.02 m past its natural len

ale4655 [162]

Answer:

(75 x 0.02) = 1.5 N

Explanation:

7 0

3 years ago

A guitar string is supposed to have a fundamental frequency 256 Hz. It currently has a fundamental frequency 248 Hz when the str

umka2103 [35]

Answer:

The tension to bring the guitar string into tune is 372.95 Hz.

Explanation:

Given;

current frequency, f₁ = 248 Hz

current tension, T₁ = 350 N

fundamental frequency, f₂ = 256

The tension on the string to bring the guitar string into tune is calculated as;

$v = \sqrt{\frac{T}{\mu} } \\\\f\lambda = \sqrt{\frac{T}{\mu} } \\\\f^2\lambda^2 = \frac{T}{\mu} \\\\f^2 = \frac{T}{\mu \lambda^2}\\\\let \ {\mu \lambda^2} = k\\\\f^2 =\frac{T}{k} \\\\k = \frac{T}{f^2} \\\\\frac{T_1}{f_1^2} = \frac{T_2}{f_2^2}\\\\T_2 = \frac{T_1 f_2^2}{f_1^2} \\\\T_2 = \frac{350 \times 256^2}{248^2} \\\\T_2 = 372.95 \ Hz$

Therefore, the tension to bring the guitar string into tune is 372.95 Hz.

3 0

3 years ago

Câu 1. Trong dao động điều hoà, phát biểu nào sau đây là không đúng ?

kobusy [5.1K]

Answer:

whatttttttttttt

Explanation:

the ಠᴥಠಠᴥಠಠᴥಠಠᴥಠಠᴥಠಠᴥಠಠᴥಠಠᴥಠ

3 0

2 years ago