One of Kepler's laws is that the orbits of planets are elliptical. It's not a suggestion.
BTW, circles are ellipses too, but so special that their likelihood is close to zero.
As long as they're both on the same planet, the greater mass always has the greater weight. In this question, Object-A has the greater mass, so it weighs more that Object-B does.
Answer: What is this supposed to be converted into?
Explanation:
Answer:
162500000.
Explanation:
Given that
Diameter of the wire , d= 1.8 mm
The length of the wire ,L = 15 cm
Current ,I = 260 m A
The charge on the electron ,e= 1.6 x 10⁻¹⁹ C
We know that Current I is given as
![I=\dfrac{q}{t}](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7Bq%7D%7Bt%7D)
I=Current
q=Charge
t=time
q= I t
q= 260 m t
The total number of electron = n
q= n e
![n=\dfrac{260\times 10^{-3}\ t}{1.6\times 10^{-9}}](https://tex.z-dn.net/?f=n%3D%5Cdfrac%7B260%5Ctimes%2010%5E%7B-3%7D%5C%20t%7D%7B1.6%5Ctimes%2010%5E%7B-9%7D%7D)
n=162500000 t
![\dfrac{n}{t}=16250000](https://tex.z-dn.net/?f=%5Cdfrac%7Bn%7D%7Bt%7D%3D16250000)
The number of electron passe per second will be 162500000.
Answer: 18.9 m
Explanation:
i did the kinematic equation & found the answer.