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Pie
2 years ago
9

What are dreams, where do they originate from, why do we have dreams, and are they psychic visions or something? Please explain

in 5 sentences.
Physics
1 answer:
Slav-nsk [51]2 years ago
8 0
Dreams are stories of images, emotions, and ideas that our mind make when we sleep. perhaps, we dream because of unconscious wishes and desires. they can be psychic visions, our dreams can predict the future.
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you are working in a physics lab where you have made a simple circuit with a battery and bulb in which part of your circuit is t
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The current moves in the terminal.

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3 years ago
Which color of the visible light waves has the highest energy level?
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1) Which of the following statements about physical models is not true?
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1. "<span>Physical models are usually in the form of a graph" is the statement among the statements given about physical models that is not true. The correct option among all the options that are given in the question is the third option or option "c".

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3 years ago
How long does it take (in minutes) for light to reach venus from the sun, a distance of 1.152 × 108 km?
7nadin3 [17]
Using the precise speed of light in a vacuum (299,792,458 \ \frac{m}{s}), and your given distance of 1.152 * 10^{8} km, we can convert and cancel units to find the answer. The distance in m, using \frac{1000 \ m}{1 \ km}, is 1.152 * 10^{11} m. Next, for the speed of light, we convert from s to min, using \frac{1 \ min}{60 \ s}, so we divide the speed of light by 60. Finally, dividing the distance between the Sun and Venus by the speed of light in km per min, we find that it is 6.405 min.

7 0
3 years ago
You pull straight up on the string of a yo-yo with a force 0.35 N, and while your hand is moving up a distance 0.16 m, the yo-yo
jarptica [38.1K]

Answer:

a) 0.138J

b) 3.58m/S

c) (1.52J)(I)

Explanation:

a) to find the increase in the translational kinetic energy you can use the relation

\Delta E_k=W=W_g-W_p

where Wp is the work done by the person and Wg is the work done by the gravitational force

By replacing Wp=Fh1 and Wg=mgh2, being h1 the distance of the motion of the hand and h2 the distance of the yo-yo, m is the mass of the yo-yo, then you obtain:

Wp=(0.35N)(0.16m)=0.056J\\\\Wg=(0.062kg)(9.8\frac{m}{s^2})(0.32m)=0.19J\\\\\Delta E_k=W=0.19J-0.056J=0.138J

the change in the translational kinetic energy is 0.138J

b) the new speed of the yo-yo is obtained by using the previous result and the formula for the kinetic energy of an object:

\Delta E_k=\frac{1}{2}mv_f^2-\frac{1}{2}mv_o^2

where vf is the final speed, vo is the initial speed. By doing vf the subject of the formula and replacing you get:

v_f=\sqrt{\frac{2}{m}}\sqrt{\Delta E_k+(1/2)mv_o^2}\\\\v_f=\sqrt{\frac{2}{0.062kg}}\sqrt{0.138J+1/2(0.062kg)(2.9m/s)^2}=3.58\frac{m}{s}

the new speed is 3.58m/s

c) in this case what you can compute is the quotient between the initial rotational energy and the final rotational energy

\frac{E_{fr}}{E_{fr}}=\frac{1/2I\omega_f^2}{1/2I\omega_o^2}=\frac{\omega_f^2}{\omega_o^2}\\\\\omega_f=\frac{v_f}{r}\\\\\omega_o=\frac{v_o}{r}\\\\\frac{E_{fr}}{E_{fr}}=\frac{v_f^2}{v_o^2}=\frac{(3.58m/s)}{(2.9m/s)^2}=1.52J

hence, the change in Er is about 1.52J times the initial rotational energy

5 0
2 years ago
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