<h2><u>
Answer with explanation</u>
:</h2>
Let 
be the population mean.
As per given , we have
Since the alternative hypothesis is right-tailed , so the test is a right-tailed test.
Also, population standard deviation is given 
, so we perform one-tailed z-test.
Test statistic : 
, where = Population mean
= Population standard deviation
n= sample size
= Sample mean
For n= 18 , 
, , 
, we have
P-value (for right tailed test): P(z>2.12) = 1-P(z≤ 2.12) [∵ P(Z>z)=1-P(Z≤z)]\
=1- 0.0340=0.9660
Decision : Since P-value(0.9660) > Significance level (0.01), it means we are failed to reject the null hypothesis.
[We reject null hypothesis if p-value is larger than the significance level . ]
Conclusion : We do not have sufficient evidence to show that the goal is not being met at α = .01 .
You can do C(6,2) which gives
which is
15!
Try this way:
S=S₁-S₂, where S - area of the figure, S₁ - area of the triangle, S₂ - area of the quadrangle.
S=0.5*(5+2)*(5+4)-2*4=31.5-8=23.5 in.²
Answer: 23.5 in.²
Answer:
2,48,000
Step-by-step explanation:
- Initial population of bacteria = 15,500
- Bacteria doubles after every 234 hours
- So, after 0 (zero) hours, no of bacteria = 15,500
- After 234 hours, no. of bacteria = 2(15,500) = 31,000
- After 468 hours, no. of bacteria = 2(31,000) = 62,000 (2*234 = 468)
- After 702 hours, no. of bacteria = 2(62,000) = 124,000 (3*234 = 702)
- After 936 hours, no. of bacteria = 2(124000) = 2,48,000 (4*234 = 936)
Answer:
20
Step-by-step explanation:
Simplify both sides of the equation.
−4=
r
20
−5
−4=
1
/20
r+−5
−4=
1
/20
r−5
Flip the equation.
1
/20
r−5=−4
Add 5 to both sides.
1
/20
r−5+5=−4+5
1
/20
r=1
Multiply both sides by 20.
20*(
1
/20
r)=(20)*(1)
r=20
