Answer : The concentration of
ion is, ![1.58\times 10^{-10}M](https://tex.z-dn.net/?f=1.58%5Ctimes%2010%5E%7B-10%7DM)
Solution : Given,
pH = 4.20
First we have to calculate the pOH.
As we know that,
![pH+pOH=14](https://tex.z-dn.net/?f=pH%2BpOH%3D14)
![pOH=14-pH](https://tex.z-dn.net/?f=pOH%3D14-pH)
![pOH=14-4.20](https://tex.z-dn.net/?f=pOH%3D14-4.20)
![pOH=9.8](https://tex.z-dn.net/?f=pOH%3D9.8)
Now we have to calculate the concentration of
ion.
![pOH=-\log [OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E-%5D)
![9.8=-\log [OH^-]](https://tex.z-dn.net/?f=9.8%3D-%5Clog%20%5BOH%5E-%5D)
![[OH^-]=1.58\times 10^{-10}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D1.58%5Ctimes%2010%5E%7B-10%7DM)
Therefore, the concentration of
ion is, ![1.58\times 10^{-10}M](https://tex.z-dn.net/?f=1.58%5Ctimes%2010%5E%7B-10%7DM)
No Ag cannot react with NaOH because Ag is less reactive than Na in the reactivity series and can't displace it
Because if no one gets sick the hospitals will get no patients to cure and there would be overpopulation.
Answer ;
As an inert gas is nonreactive and thus, it won't affect the equilibrium
1 mole of NaCl contains 6.022×10^23 particles
∴. 922 moles of NaCl contains.... (multiplication of the 2 numbers)