Answer:- 14.0 moles of hydrogen present in 2.00 moles of ![[tex]C_6H_7N](https://tex.z-dn.net/?f=%20%5Btex%5DC_6H_7N)
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Solution:- We have been given with 2.00 moles of 
and asked to calculate the grams of hydrogen present in it. It's a two step conversion problem. In first step we convert the moles of the compound to moles of hydrogen as one mol of the compound contains 7 moles of hydrogen. In next step the moles are converted to grams on multiplying the moles by atomic mass of H. The calculations are shown as:
= 14.0 g H
So, there are 14.0 g of hydrogen in 2.00 moles of .
Answer:
Explanation:
Balanced equation
2Fe + 3H2SO4 → Fe2(SO4)3 + 3H2.
Subscripts
This is a very important question. It is good to know the answer. The subscripts cannot be altered because that's the way the molecule is constructed. For example, it takes 2 Hydrogens to mix with one SO4 ion. That's the way Sulfuric acid is found in nature. There are no other ways to write 2H+ and SO4-2
You can alter (and you must alter) the way the molecules react with each other. You need to make sure that the Conservation of Mass law is always being obeyed. So when you have 6 H's on the left, you must have the same number on the right. 6 grams of hydrogen on the left = 5 hydrogens on the right.
It means there is a lot of the same thing and not many others
<u>Answer:</u> This violates the law of constant composition.
<u>Explanation:</u>
Dalton's theory is based on mainly two laws, which are law of conservation of mass and law of constant composition.
Law of constant composition states that a compound always contain the elements in the fixed ratio by their masses.
For Example: In water 
, the hydrogen and oxygen are present in the fixed ratio of 1 : 9 by their mass.
We are given:
A sample of titanium dioxide having 59.95 % of titanium and another sample of titanium dioxide having 60.10 % of titanium.
As, the compound is titanium dioxide. So, the mass percent of titanium must remain the same in both the elements.
Hence, this violates the law of constant composition.
Answer:
Mass = 20,000 g
Explanation:
Given data:
Mass of MgO formed = ?
Mass of Mg react = 12 Kg (12 Kg × 1000/1 Kg = 12000 g)
Solution:
Chemical equation:
2Mg + O₂ → 2MgO
Number of moles of Mg:
Number of moles = mass/molar mass
Number of moles = 12000 g/ 24 g/mol
Number of moles = 500 mol
Now we will compare the moles of Mg and MgO.
Mg : MgO
2 : 2
500 : 500
Mass of MgO:
Mass = number of moles × molar mass
Mass = 500 mol × 40 g/mol
Mass = 20,000 g
