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3 years ago

Sulfuryl chloride decomposes at high temperatures to produce sulfur dioxide and chlorine gases:

Chemistry

1 answer:

den301095 [7]3 years ago

7 0

Answer:

[SO2Cl2] = = 0.015 M [SO2] = = 0.0027 M [Cl2] = = 0.0027 M Q = = = 4.8 × 10−4

No. Q < Kc, so reaction will shift to the right.

Explanation:

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What would be the mass in grams of 1.204 x 1024 molecules of sulfur dioxide

melomori [17]

Answer:

mass of sulfur = 96 g

Explanation:

no of moles of sulfur dioxide in $1.204\times 10^{24}$ molecules = $\frac{1.204\times 10^{24}}{avagadro number }= \frac{1.204\times 10^{24}}{6.023\times 10^{23}}$

= 2 moles

therefore mass of sulfur dioxide = moles×atomic number

=2×(16+32)

=96

6 0

3 years ago

he rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy . If the rate c

Leya [2.2K]

The question is incomplete, here is the complete question:

The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy Ea = 71.0 kJ/mol . If the rate constant of this reaction is 6.7 M^(-1)*s^(-1) at 244.0 degrees Celsius, what will the rate constant be at 324.0 degrees Celsius?

Answer: The rate constant at 324°C is $61.29M^{-1}s^{-1}$

Explanation:

To calculate rate constant at two different temperatures of the reaction, we use Arrhenius equation, which is:

$\ln(\frac{K_{324^oC}}{K_{244^oC}})=\frac{E_a}{R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_{244^oC}$ = equilibrium constant at 244°C = $6.7M^{-1}s^{-1}$

$K_{324^oC}$ = equilibrium constant at 324°C = ?

$E_a$ = Activation energy = 71.0 kJ/mol = 71000 J/mol (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

$T_1$ = initial temperature = $244^oC=[273+244]K=517K$

$T_2$ = final temperature = $324^oC=[273+324]K=597K$

Putting values in above equation, we get:

$\ln(\frac{K_{324^oC}}{6.7})=\frac{71000J}{8.314J/mol.K}[\frac{1}{517}-\frac{1}{597}]\\\\K_{324^oC}=61.29M^{-1}s^{-1}$

Hence, the rate constant at 324°C is $61.29M^{-1}s^{-1}$

8 0

3 years ago

How many carbon atoms are represented by the model below A) 0 B) 3 C) 2 D) 1

Bogdan [553]

Answer:

Option (B) 3.

Explanation:

In the model represented above, the two extreme represent carbon atoms since no other group are attached to it. The joint at the middle also represent carbon atom.

Thus, we can write a more simplify illustration for the model above as

C—C—C

From the above illustration, we can see that the model contains 3 carbon atom.

5 0

2 years ago

365,000,000 scientific notation

bekas [8.4K]

3.65 X 10 to the power of 8

6 0

2 years ago

When a gas is given off as a liquid boils it is an example of a?

____ [38]

This is an example of a condenser

7 0

3 years ago