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3 years ago

Every force has one and only one 3rd law pair force. every force has one and only one 3rd law pair force.

Physics

2 answers:

riadik2000 [5.3K]3 years ago

8 0

The correct answer is a. It is true

Likurg_2 [28]3 years ago

7 0

I would have to say B failed because I think I read something about it being only 2law not 3

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A heat engine cycle is executed with steam in the saturation dome. The pressure of steam is 1.1 MPa during heat addition and 0.3

klio [65]

Answer:The highest possible efficiency of this heat engine is 11%

Explanation:

Saturated water temperature at P1, Pressure in Heat addition,

1.1 MPa=185°C +273= 458K

Saturated water temperature at P2, Pressure in Heat rejection,

0.3MPa=133.5°C+ 273=406.5K

The highest possible efficiency of any heat engine is the Carnot efficiency given as

Carnot efficiency, ηmax = 1- (T2/ T1)

1- (406.5K/458K)

1-0.88755=0.112

=11%

8 0

2 years ago

!!PLEASE ANSWER ASAP!!

galina1969 [7]

A. elastic motion because that's the answer

8 0

2 years ago

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PLEASE HELP!!!!!!!!! 30 POINTS

ivolga24 [154]

Answer: experiment data is the things you do in the experiment and the result is the answer

4 0

2 years ago

A car accelerates from 300 km/h to 140 km/h in 2.53 seconds. what is the distance covered?

Snowcat [4.5K]

Answer:

Acceleration = Change in Velocity/Time

Change in Velocity = 36-18 = 18 km/h=5 m/s

Time= 5 Seconds

Acceleration = 5/5= 1 m/s2

Equation of motion,s=ut+(1/2)at2

u=18 km/h=5 m/s

t=5 s

a=1 m/s2

s= (5*5)+(1/2*1*5*5)

s=25+12.5 i.e., s=37.5 m

Hope you are clear with my explanations

7 0

2 years ago

A 50kg meteorite moving at 1000 m/s strikes Earth. Assume the velocity is along the line joining Earth's center of mass and the

zysi [14]

As per the question, the mass of meteorite [ m]= 50 kg

The velocity of the meteorite [v] = 1000 m/s

When the meteorite falls on the ground, it will give whole of its kinetic energy to earth.

We are asked to calculate the gain in kinetic energy of earth.

The kinetic energy of meteorite is calculated as -

$Kinetic\ energy\ [K.E]\ =\frac{1}{2} mv^2$

$=\frac{1}{2}50kg*[1000\ m/s]^2$

$=\frac{1}{2}50* 10^{6}\ J$

$=25*10^6\ J$

Here, J stands for Joule which is the S.I unit of energy.

$Hence,\ the\ kinetic\ energy\ gained\ by\ earth\ is\ 25*10^6\ J$

4 0

3 years ago

Read 2 more answers