Think its Positive
hope this helpes
Assuming the accleration applied was constant, we have



Then the force applied to the ball is given by


The statement "<span>When an electron is added to a neutral atom of an element to form a negative ion, the resulting change in energy is referred to as the electron potential of that element." is false.
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I think it’s A not 100% sure
Agility is the answer. Hope this helps have an awesome day!